Average = (0.64204 + 0.64203 + 0.64202 + 0.64201)/ 4
=2.5681/ 4
=0.642025
Sum of 50 result = sum of 30 result + sum of 20 result.
= 30 x 20 + 20 x 30
= 1200
Fifth result = sum of all five result - sum of first four result.
= 5 x 46 - 4 x 45
= 230 -180
=50
Average = ( 3 + 6 + 9 + 12 + 15 + 18 + 21 + 24 + 27 ) / 9
= 3(1+2+3+4+5+6+7+8+9)/9
= ( 45 / 3 )
= 15
Let second number = x
So, first number = 2x and third number= 4x
? ( x + 2x + 4x ) / 3 = 56
? 7x = 168
? x = 24
So the numbers are 48,24, 96,
Since a, b, c, d, e are 5 consecutive numbers so
b = a + 2.
c = a + 4.
d = a + 6.
e = a + 8.
Average = (a + b + c + d + e)/ 5
= [a + (a + 2 ) + (a +4 ) + (a+6 )+ (a+8)] / 5
= (5a+20) / 5
= a + 4
weight of (A + B ) = (2 X 40 ) Kg = 80 kg
weight of (B + C ) = (2 X 43) kg = 86 kg
weight of (A + 2B +C ) = (80 + 86) kg = 166 kg
weight of (A + B + C ) = (3 X 45) kg = 135 kg
weight of B = (166-135) kg = 31 kg
Weight of new student = Total weight of all 20 students - Total weight of initial 19 students
= (20 x 14.8 - 19 x 15) kg
= 11 kg.
Total Increase = 8 x 2.5 = 20 kg.
weight of new man = (56 + 20) kg = 76 kg
Let C's earning = Rs. y.
Then, B's earning = Rs. (y + 20)
and A's earning = Rs. 2y
? 2y + y + 20 + y= 3 x 60
? 4x = 160
? x = 40
Let original strength = y
Then , 40y + 12 x 32 = ( y + 12) x 36
? 40y + 384 = 36y + 432
? 4y = 48
? y = 12
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