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Home ‣ Aptitude ‣ Problems on H.C.F and L.C.M Comments
- Question
- What least number must be subtracted from 1294 so that the remainder when divided by 9, 11, 13 will leave in each case the same remainder 6?
Options- A. 0
- B. 1
- C. 2
- D. 3
- Correct Answer
- 1
ExplanationL. C .M of 9, 11, 13 is 1287
On dividing 1294 by 1287, the remainder is 7 .
? 1 must be subtracted from 1294, so that 1293 when divided by 9, 11, 13 leaves in each case the same remainder 6 . - 1. The number of prime factors in the expression (6) 10 x (7) 17 x (11) 27 is?
Options- A. 54
- B. 64
- C. 71
- D. 81 Discuss
- 2. The measuring rods are 64 cm, 80 cm and 96 cm in length. The least length of cloth that can be measured exact number of times using any one of the above rods bis?
Options- A. 0.96 m
- B. 19.20 m
- C. 9.60 m
- D. 96.00 m Discuss
- 3. The least number which when divided by 15, 27, 35 and 42, leaves in each case a remainder 7 is?
Options- A. 1883
- B. 1897
- C. 1987
- D. 2007 Discuss
- 4. The greatest number of four digits which is divisible by each one of the numbers 12, 18 21 and 28 is?
Options- A. 9848
- B. 9864
- C. 9828
- D. 9636 Discuss
- 5. The least number, which when divided by 16, 18 and 21 leaves the remainder 3, 5 and 8 respectively, is?
Options- A. 893
- B. 992
- C. 995
- D. 1024 Discuss
- 6. The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder is?
Options- A. 1677
- B. 1683
- C. 2523
- D. 3363 Discuss
- 7. The greatest number by which if 1657 and 2037 are divided the remainders will be 6 and 5 respectively, is?
Options- A. 127
- B. 235
- C. 260
- D. 305 Discuss
- 8. Six bell commence tolling together and toll at intervals of 5, 10, 15, 20, and 30 s, respectively. In 60 min, how many times do they toll together?
Options- A. 20
- B. 15
- C. 13
- D. 11 Discuss
- 9. If the HCF of two positive integers is 26. Then their LCM cannot be?
Options- A. 78
- B. 104
- C. 144
- D. 234 Discuss
- 10. If the HCF of m and n is 1, then what are the HCF of m + n, m and HCF of m - n, n, respectively (where, m > n)?
Options- A. 2 and 1
- B. 1 and 1
- C. 1 and 2
- D. Cannot be determined Discuss
Problems on H.C.F and L.C.M
Search Results
Correct Answer: 64
Explanation:
Since 2, 3, 7, 11 are prime numbers and the given expression is
210 x 310 x 717 x 1127
So the number of prime factors in the given expression is (10 + 10 + 17 + 27 ) = 64.
Correct Answer: 9.60 m
Explanation:
Required length = L. C . M of (64, 80, 96) cm
= 960 cm
= 9.60 m.
Correct Answer: 1897
Explanation:
Required Number = (LCM of 15, 27, 35 and 42) + 7
= 1890 + 7
= 1897
Correct Answer: 9828
Explanation:
Required number is divisible by the L . C . M of 12, 18, 21, 28 i.e 252.
Now, greatest number of four digits = 9999
On dividing 9999 by 252, the remainder is 171
? Required number = (9999 - 171) = 9828.
Correct Answer: 995
Explanation:
Here (16 - 3) = 13,
(18 - 5) = 13 and
(21 - 8 ) = 13
So, required number = (L . C . M of 16, 18, 21) - 13
= (1008 - 13)
= 995
Correct Answer: 1683
Explanation:
L.C.M of 5, 6 , 7, 8 is 840
So, the number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2
? Required number = (840 x 2 + 3 ) = 1683
Correct Answer: 127
Explanation:
Required number = H.C.F of (1657 - 6) and (2037 - 5)
= H.C.F of 1651 and 2032
= 127
Correct Answer: 13
Explanation:
LCM of 5, 10, 15, 20, 25 and 30 is 300. So, the bell will toll together after every 300s (5min).
So, the number of times they toll together = 60/5 + 1=13
Correct Answer: 144
Explanation:
LCM of the number is always divisible by the HCF of the same numbers.
So, 78, 104 and 234 are all divisible by 26. Whereas, 144 is not divisible by 26.
Thus, 144 cannot be the LCM of the number whose HCF is 26.
Correct Answer: 1 and 1
Explanation:
The HCF of m and n is 1, so m and n are prime number.
Let m = 7 and n = 5 ? m + n = 12
HCF of(m + n)and m = HCF of 12 and 7 = 1
Similarly, HCF of (m - n) and n = 1
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