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Home ‣ Aptitude ‣ Problems on H.C.F and L.C.M Comments
- Question
- The least number which when divided by 15, 27, 35 and 42, leaves in each case a remainder 7 is?
Options- A. 1883
- B. 1897
- C. 1987
- D. 2007
- Correct Answer
- 1897
ExplanationRequired Number = (LCM of 15, 27, 35 and 42) + 7
= 1890 + 7
= 1897 - 1. The greatest number of four digits which is divisible by each one of the numbers 12, 18 21 and 28 is?
Options- A. 9848
- B. 9864
- C. 9828
- D. 9636 Discuss
- 2. The least number, which when divided by 16, 18 and 21 leaves the remainder 3, 5 and 8 respectively, is?
Options- A. 893
- B. 992
- C. 995
- D. 1024 Discuss
- 3. About the number of pairs which have 16 as their H.C.F and 136 as their L.C.M. We can definitely say that?
Options- A. Only one such pair exists
- B. Only two such pair exists
- C. Many such pairs exists
- D. No such pair exists Discuss
- 4. The product of two numbers is 1600 and their H.C.F is 5. The L.C.M. of the numbers is?
Options- A. 320
- B. 1605
- C. 1595
- D. 8000 Discuss
- 5. The H.C.F of two number is 16 and their L.CM is 160. If one of the numbers is 32, then the other number is?
Options- A. 48
- B. 80
- C. 96
- D. 112 Discuss
- 6. The measuring rods are 64 cm, 80 cm and 96 cm in length. The least length of cloth that can be measured exact number of times using any one of the above rods bis?
Options- A. 0.96 m
- B. 19.20 m
- C. 9.60 m
- D. 96.00 m Discuss
- 7. The number of prime factors in the expression (6) 10 x (7) 17 x (11) 27 is?
Options- A. 54
- B. 64
- C. 71
- D. 81 Discuss
- 8. What least number must be subtracted from 1294 so that the remainder when divided by 9, 11, 13 will leave in each case the same remainder 6?
Options- A. 0
- B. 1
- C. 2
- D. 3 Discuss
- 9. The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder is?
Options- A. 1677
- B. 1683
- C. 2523
- D. 3363 Discuss
- 10. The greatest number by which if 1657 and 2037 are divided the remainders will be 6 and 5 respectively, is?
Options- A. 127
- B. 235
- C. 260
- D. 305 Discuss
Problems on H.C.F and L.C.M
Search Results
Correct Answer: 9828
Explanation:
Required number is divisible by the L . C . M of 12, 18, 21, 28 i.e 252.
Now, greatest number of four digits = 9999
On dividing 9999 by 252, the remainder is 171
? Required number = (9999 - 171) = 9828.
Correct Answer: 995
Explanation:
Here (16 - 3) = 13,
(18 - 5) = 13 and
(21 - 8 ) = 13
So, required number = (L . C . M of 16, 18, 21) - 13
= (1008 - 13)
= 995
Correct Answer: No such pair exists
Explanation:
H.C.F. of two numbers divides their L.C.M. exactly. Since 16 is not a factor of 136, it states that there does not exist any pair of numbers with H,C.F. 16 and L.C.M. 136.
Correct Answer: 320
Explanation:
Product of two numbers = LCM of two numbers x HCF of two numbers.
? 1600 = LCM x 5
? LCM = 320
Correct Answer: 80
Explanation:
Product of two numbers = LCM of two numbers x HCF of two numbers.
? N x 32 = 160 x 16
? N = 80
Correct Answer: 9.60 m
Explanation:
Required length = L. C . M of (64, 80, 96) cm
= 960 cm
= 9.60 m.
Correct Answer: 64
Explanation:
Since 2, 3, 7, 11 are prime numbers and the given expression is
210 x 310 x 717 x 1127
So the number of prime factors in the given expression is (10 + 10 + 17 + 27 ) = 64.
Correct Answer: 1
Explanation:
L. C .M of 9, 11, 13 is 1287
On dividing 1294 by 1287, the remainder is 7 .
? 1 must be subtracted from 1294, so that 1293 when divided by 9, 11, 13 leaves in each case the same remainder 6 .
Correct Answer: 1683
Explanation:
L.C.M of 5, 6 , 7, 8 is 840
So, the number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2
? Required number = (840 x 2 + 3 ) = 1683
Correct Answer: 127
Explanation:
Required number = H.C.F of (1657 - 6) and (2037 - 5)
= H.C.F of 1651 and 2032
= 127
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