Given factors
2 x 3 x 7 x 9; 2 x 3 x 9 x 11; 2 x 3 x 4 x 5
? Required HCF = Product of common prime factors having least powers = 2 x 3
Required LCM = a x 2 x 5 x 7 = 70a
Required number = LCM of (12, 15, 20, 24) + 2
= 120 + 2 = 122
Required measure = HCF of 403, 434 and 465 = 31 cm
Let the numbers be 2x and 3x.
So, their LCM = 6x
However, the LCM is given as 48
? 6x = 48
? x=8
So, the numbers are 16 and 24.
Hence, their sum is 40.
First number = 2 x 44 = 88
Second number = (LCM x HCF ) / First number
? Second number = 44 x 264 / 88 = 132.
We known that,
LCM of fractions = (LCM of numerators) / (HCF of denominators)
? Required LCM = (LCM of 1, 2, 5, and 4) / (HCF of 3, 9, 6 and 27)
? = 20/3
Required LCM = (LCM of 2, 3, 4, 9) / (HCF of 3, 5, 7, 13)
= (4 x 9)/1
= 36
HCF of 18 and 15
18 = 2 x 3 x 3
15 = 3 x 15 = 3
LCM of 18 and 15 = 2 x 3 x 3 x 5 = 90
? Product of HCF and LCM of both numbers = 3 x 90 = 270
Let the other number = N
Product of LCM and HCF = Product of two numbers
Then, N x 75 = 15 x 225
? N = (15 x 225)/75 = 45
Let the numbers are N, 2N and 3N.
Where, N = HCF
Given that, N = 23
? The numbers are 23, 46 and 69.
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