The number of prime factors in the given product
= (222 + 333 + 555)
= 1110.
Required number = (L . C . M of 21, 28, 36, 45 ) + 3
= (1260 + 3 )
= 1263
7/9, 5/7, 3/5
3/7
L. C . M of 2/7, 3/14 and 5/ 3 = ( LCM of 2, 3 and 5) / ( HCF of 7, 14 and 3)
= 30
Straight forward answer 12, 24, 36
First number = 2 x 44 = 88
Second number = (LCM x HCF ) / First number
? Second number = 44 x 264 / 88 = 132.
Let the numbers be 2x and 3x.
So, their LCM = 6x
However, the LCM is given as 48
? 6x = 48
? x=8
So, the numbers are 16 and 24.
Hence, their sum is 40.
Required measure = HCF of 403, 434 and 465 = 31 cm
Required number = LCM of (12, 15, 20, 24) + 2
= 120 + 2 = 122
Required LCM = a x 2 x 5 x 7 = 70a
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