Required number = (L . C . M of 21, 28, 36, 45 ) + 3
= (1260 + 3 )
= 1263
7/9, 5/7, 3/5
3/7
L. C . M of 2/7, 3/14 and 5/ 3 = ( LCM of 2, 3 and 5) / ( HCF of 7, 14 and 3)
= 30
Straight forward answer 12, 24, 36
The difference of requisite number must be 12 and each one must be divisible by 12, so the numbers are 84, 96.
The number of prime factors in the given product
= (222 + 333 + 555)
= 1110.
First number = 2 x 44 = 88
Second number = (LCM x HCF ) / First number
? Second number = 44 x 264 / 88 = 132.
Let the numbers be 2x and 3x.
So, their LCM = 6x
However, the LCM is given as 48
? 6x = 48
? x=8
So, the numbers are 16 and 24.
Hence, their sum is 40.
Required measure = HCF of 403, 434 and 465 = 31 cm
Required number = LCM of (12, 15, 20, 24) + 2
= 120 + 2 = 122
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