If 2x - |
|
= 6, then the value of x2 + |
|
is |
2x | 16x2 |
If x = 2 + ?3, y = 2 - ?3, then the value of |
|
is |
x3 + y3 |
As per the given question , we have
a2 + b2 + c2 = 2 (a b c) 3
⇒ a2 + b2 + c2 = 2a + 2b + 2c + 3 = 0
⇒ a2 2a + 1 + b2 + 2b + 1 + c2 + 2c + 1 = 0
⇒ (a 1)2 + (b + 1)2 + (c + 1)2 = 0
[If x2 + y2 + z2 = 0 ⇒ x = 0; y = 0; z = 0]
∴ a 1 = 0 ⇒ a = 1
b + 1 = 0 ⇒ b = 1
c + 1 = 0 ⇒ c = 1
∴ 2a 3b + 4c = 2 + 3 4 = 1
Given in the question ,
x - 1 = ?2 + ?3
On squaring both sides ,
x 2 ? 2x + 1 = 2 + 3 + 2?6
? x 2 - 2x - 4 = 2 ?6
On squaring again,
? x4 + 4x2 + 16 ? 4x3 ? 8x2 + 16x = 24
? x4 ? 4x3 ? 4x2 + 16x ? 8 = 0
? 2x4 ? 8x3 ? 8x2 + 32x ? 16 = 0
? 2x4 ? 8x3 ? 5x2 + 26x ? 28 ? 3x2 + 6x + 12 = 0
? 2x4 ? 8x3 ? 5x2 + 26x ? 28 = 3x2 ? 6x ? 12
? 2x4 ? 8x3 ? 5x2 + 26x ? 28 = 3 (x2 ? 2x ? 4)
? 2x4 ? 8x3 ? 5x2 + 26x ? 28 = 3 x 2?6 = 6 ?6
If x = |
|
, then the value of |
|
+ |
|
is |
a + b | x - 2a |
x - 2b |
If x = ?a + |
|
, y = ?a - |
|
, then the value of |
?a |
?a |
We have p3 + q3 + r3 ? 3pqr = (p + q + r) (p2 + q2 + r2 ?pq ? qr - rp)
Here p = a ? 4, q = b ? 3, r = c ?1
So, given expression is (p + q + r) (p2 + q2 + r2 ? pq ? qr ? rp)
= (a ? 4 + b ? 3 + c ? 1) (p2 + q2 + r2 ? pq ? qr ? rp)
= (a + b + c ? 8) (p2 + q2 + r2 ? pq ? qr ? rp)
= (8 ? 8) (p2 + q2 + r2 ? pq ? qr ? rp)
? (a ? 4)3 + (b ? 3)3 + (c ? 1)3 ? 3 (a ? 4) (b ? 3) (c ? 1) = 0
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