Given in the question ,
x - 1 = ?2 + ?3
On squaring both sides ,
x 2 ? 2x + 1 = 2 + 3 + 2?6
? x 2 - 2x - 4 = 2 ?6
On squaring again,
? x4 + 4x2 + 16 ? 4x3 ? 8x2 + 16x = 24
? x4 ? 4x3 ? 4x2 + 16x ? 8 = 0
? 2x4 ? 8x3 ? 8x2 + 32x ? 16 = 0
? 2x4 ? 8x3 ? 5x2 + 26x ? 28 ? 3x2 + 6x + 12 = 0
? 2x4 ? 8x3 ? 5x2 + 26x ? 28 = 3x2 ? 6x ? 12
? 2x4 ? 8x3 ? 5x2 + 26x ? 28 = 3 (x2 ? 2x ? 4)
? 2x4 ? 8x3 ? 5x2 + 26x ? 28 = 3 x 2?6 = 6 ?6
If a = |
|
, b = |
|
, then the value of |
?3 + ?2 | ?3 - ?2 |
|
+ |
|
is : | |
b | a |
Given in the question,
Points (a, b) and [(a + 3), (b + k)] will satisfy the equation x ? 3y + 7 = 0.
Points (a, b) in the equation x ? 3y + 7 = 0, We will get
? a ? 3b + 7 = 0 ...................... (i)
Points (a + 3), (b + k) in the equation x ? 3y + 7 = 0, We will get
a + 3 ? 3 (b + k) + 7 = 0
? a + 3 ? 3b ? 3 k + 7 = 0 (Rearrange the equation)
? a ? 3b + 7 + 3 ? 3 k = 0 (a ? 3b + 7 = 0 , Put the value from Equation (1) ), We will get
? 0 + 3 ? 3k = 0
? 3k = 3
? k = 1
According to question ,
PQ = ?( 5 - 2 )2 + ( 4 - 0 )2
PQ = ?9 + 16 = 5
? Area of circle = ?r2
Area of circle = 25 ? sq. units
As per the given question , we have
a2 + b2 + c2 = 2 (a b c) 3
⇒ a2 + b2 + c2 = 2a + 2b + 2c + 3 = 0
⇒ a2 2a + 1 + b2 + 2b + 1 + c2 + 2c + 1 = 0
⇒ (a 1)2 + (b + 1)2 + (c + 1)2 = 0
[If x2 + y2 + z2 = 0 ⇒ x = 0; y = 0; z = 0]
∴ a 1 = 0 ⇒ a = 1
b + 1 = 0 ⇒ b = 1
c + 1 = 0 ⇒ c = 1
∴ 2a 3b + 4c = 2 + 3 4 = 1
If x = 2 + ?3, y = 2 - ?3, then the value of |
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is |
x3 + y3 |
If 2x - |
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= 6, then the value of x2 + |
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is |
2x | 16x2 |
If x = |
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, then the value of |
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+ |
|
is |
a + b | x - 2a |
x - 2b |
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