Let the greatest, middle and smallest fraction be P, Q and R respectively in decreasing order.
According to the question.
(Greatest fraction) / (Smallest fraction) = 7/6
? P/R = 7/6
? P = 7R/6 ....(i)
and Q = 7/6 - 1/3 = 7 - 2/6 = 5/6 (ii)
Now, P + Q + R = 211/24 (iii )
Substitute the value of P and Q from Eqs. (i), (ii) and put in Eqs (iii), we get
? 7R/6 + 5/6 + R = 59/24
? (7R + 5 + 6R)/6 = 59/24
? (13R + 5) / 6 = 59/24
? 13R = (59/4) - 5 = 39/4
? R = 39 / (4 x 13)
? R = 3/4
On putting the value of R in Eq. (i), we get
P = 7R/6 = (7/6) x (3/4) = 7/8
Here sum is put on compound interest,
? P.W. = A / (1 + r / 100)n = 2420 / (1 + 10 / 100)2 = 2420 x 100 / 121 = Rs. 2000
? T.D. = P.W. - P
? True discount = 2420 - 2000 = Rs. 420
The Sum of the digits in each number, Except 324 is 10.
The given number series follows the pattern that,
24×0 + 4 = 4
4×1 + 9 = 13
13×2 + 16 = 42
42×3 + 25 = 151
151×4 + 36 = 640
Therefore, the odd number in the given series is 41
From the beginning, the next term comes by adding prime numbers in a sequence of 2, 3, 5, 7, 9, 11, 13... to its previous term. But 165 will not be in the series as it must be replaced by 166 since 153+13 = 166.
The given number series follows a pattern that
196, 169, 144, 121, 100, 81, ?
-27 -25 -23 -21 -19 -17
=> 81 - 17 = 64
Therefore, the series is 196, 169, 144, 121, 100, 81, 64.
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