Let A has ? 200 at the starting of game, then B has ? 100 at the starting of game.
After the game, money left with A = 200 - 200/3 = ? 400/3
? Total money with B = 100 + 200/3 = ? 500/3
Let the fraction of money lost by B = N
Then, 500/3 - N x 500/3 = 400/3 + N x 500/3
? 500/3 - 400/3 = 500N/3 + 500N/3
? 100/3 = 1000N/3
? N = (100/3) x (3/1000) = 1/10
so, the fraction of money lost is 1/10.
Let x% of y = y% of A, then
? xy / 100 = yA/100
? A = (xy/100) x (100/y) = x
Let 371/2% of A = 900
? {(75/2) x A} x 100 = 900
? A = (900 x 2 x 100) / 75 = 2400
So, 621/2% of A = (125/2) x (1/100) x 2400 =1500
Let A - 6% of A = AB.
? (94 x A) / 100 = AB
? B = 0.94
Let original price = Rs. 100
? Increase price = Rs. 160
? Decrease on Rs. 160 = Rs. 60
? Decrease on Rs. 100 = (60/160) x 100 % = 371/2%
?(3.6/100) x 40
= ?1.44 = 1.2
Minimum passing marks = 50 + 50 = 100
Let the total marks = x
Then, 50% of x = 100
? x = (100/50) x 100 = 200
Profit or loss percent = ab/100 %
= (20 x 20)/100 %
= -4%
5% of 50% of 500
= (5/100) x (50/100) x 500
= 12.5
Let the required amount of money be N.
Then, N x 25% = 180 x 121/2%
? N = (180 x 12.5)/25
= ? 90
Monthly income of a person = ? 5000
Increment in income = (30/100) x 5000 = 1500
New income = 5000 + 15000 = ? 6500
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