0.2341 = (2341 - 2) / 9990 = 2339/9990
Let the amount be ? a
According to the question,
a x 5/12= 33/4 x 100
? 5a/12 = 15/4 x 100
? a = 12/5 x 15/4 x 100
? a = 12 x 15 x 100/4 x 5
? a = ? 900
If the fraction a/b is positive,
then a > 0 ..............(i)
and b > 0 ..............(ii)
Multiply (i) and (ii)
So ab > 0 must be true.
Let number of boys in school are B and Girls are G.
Total number of students participated
= (B x 1/4 + G x 3/8)
= (B/4 + 3G/8)
? Required percentage
= ((B/4 + 3G/8)/(B + G) x 100%)
Clearly, given data is inadequate.
If the required fraction be P
According to the question
(P x P) / (1/P) = 1826/27
? P3 = 512/27
? P = 8/3 = 22/3
2 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)]
= 2 x [(36 x 48 x 250) / (12 x 9 x 5)]
= 2 x 4 x 4 x 50 = 1600
The given number are 0.54,1.80 and 7.20
So given number can be represented as fraction 54/100, 180/100 and 720/100
H.C.F. of 54, 180 and 720 is 18
? H.C.F. of given number= 18 / 100
= 0.18
16/19 =0.842,
11/14 =0.785 and
17/22 = 0.772
? 0.772 < 0.785 < 0.842
or 17/22 < 11/14 < 16/19.
Exp. = (.35 x .0015) / (.25 x .07)
= ( 35 x 15) / (25 x 7 x 100)
= (3/100) x 100 %
= 3%
Given expression =?(0.324 x 0.081 x 4.624) / (1.5625 x 0.0289 x 72.9 x 64)
= ?( 324 x 81 x 4624) / (15625 x 289 x 729 x 64)
= ?9 / 15625
= 3 /125
= 0.024
? 0.289 / 0.00121
= ? 0.28900 / 0.00121
= ? 28900 / 121
= 170 / 11
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