Let number of boys in school are B and Girls are G.
Total number of students participated
= (B x 1/4 + G x 3/8)
= (B/4 + 3G/8)
? Required percentage
= ((B/4 + 3G/8)/(B + G) x 100%)
Clearly, given data is inadequate.
If the required fraction be P
According to the question
(P x P) / (1/P) = 1826/27
? P3 = 512/27
? P = 8/3 = 22/3
2 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)]
= 2 x [(36 x 48 x 250) / (12 x 9 x 5)]
= 2 x 4 x 4 x 50 = 1600
1/3 + 1/15 + 1/35 + 1/63 + 1/99
= [1/3 + 1/15] + 1/35 + 1/63 + 1/99
= [6/15 + 1/35] + 1/63 + 1/99
= 45/105 + 1/63 + 1/99 = [3/7 + 1/63] + 1/99
= 28/63 + 1/99 = 4/9 + 1/99
= 44 + 1/99 = 45/99 = 5/11
0.252525 ..... = 0.25= 25/99
= 0.142857 / 0.285714
= [(142857 / 999999) / (285714 / 999999)]
= 142857 / 285714
= 1 / 2
If the fraction a/b is positive,
then a > 0 ..............(i)
and b > 0 ..............(ii)
Multiply (i) and (ii)
So ab > 0 must be true.
Let the amount be ? a
According to the question,
a x 5/12= 33/4 x 100
? 5a/12 = 15/4 x 100
? a = 12/5 x 15/4 x 100
? a = 12 x 15 x 100/4 x 5
? a = ? 900
0.2341 = (2341 - 2) / 9990 = 2339/9990
The given number are 0.54,1.80 and 7.20
So given number can be represented as fraction 54/100, 180/100 and 720/100
H.C.F. of 54, 180 and 720 is 18
? H.C.F. of given number= 18 / 100
= 0.18
16/19 =0.842,
11/14 =0.785 and
17/22 = 0.772
? 0.772 < 0.785 < 0.842
or 17/22 < 11/14 < 16/19.
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