Given that,
a = (?2 - 1)1/3
By cubing the both side of the given equation.
a3 = ?2 - 1
Then 1/a3 = 1/?2 - 1
Now multiply and divide the above equation by ?2 + 1
? 1/a3 = ( ?2 + 1 ) / ( ?2 + 1 ) x 1/(?2 - 1 )
? 1/a3 = ( ?2 + 1 ) x 1 / ( ?2 + 1 ) x (?2 - 1 ) [ Use the formula (A + B)(A - B) = A2 - B2 ]
? 1/a3 = ( ?2 + 1 ) / ( 2 - 1 )
? 1/a3 = ?2 + 1
According to the question
( a - a-1 )3 + 3 ( a - a-1 )
= (a - 1/a)3 + 3(a - 1/a) Use the formula [ ( A - B)3 = A3 - B3 + 3AB(A - B) ]
= a3 - 1/a3 - 3 a x 1/a (a -1/a) + 3(a - 1/a)
= a3 - 1/a3 - 3 (a -1/a) + 3(a - 1/a)
= a3 - 1/a3
Pu the value of a3 and 1/a3
= ?2 -1 - ( ?2 + 1 )
= ?2 -1 - ?2 - 1
= -2
Suppose they meet after y hours .
Then, 21y - 16y = 60
? y = 12
?required distance = (16 x 12 + 21 x 12) km.
= 444 km.
Let Reena?s present age be 'K' yrs.
Given:{(K+3) x 4} - {(K-3) x 3)}
=> K = 21 yrs
So her present age is 21 yrs.
Then, her age after 1 year is 22 yrs.
Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.
suppose the ages of Sunil and Anil are 8x yr and 7x yr, respectively.
After 6 yr, = 136x + 102 = 133x + 114
136x ? 133x = 114 ? 102
3x = 12 X = 12/3 = 4
Age of Sunil = 8x = 8 × 4 = 32 yr
Present age Anil = 7x = 7 × 4 = 28 yr
Required difference = (32 ? 28) = 4 yr
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