p/q + q/p = (p2 + q2)/pq
Apply the formula of algebra
a 2+ b2 = (a + b)2 - 2ab
p/q + q/p = ( (p + q)2 - 2pq ) / pq
By substituting the pq and p + q values in given equation.
p/q + q/p = ( (p + q)2 - 2pq ) / pq
p/q + q/p = ((10)2 - 2 x 5 ) / 5
p/q + q/p = (100 - 10 )/ 5 = 90/5 = 18
p/q + q/p = 90/5 = 18
p/q + q/p = 18
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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