a2 + 1 = a ? a + 1/a = 1
On squaring both sides, we get
a2 + 1/a2 + 2 = 1
? a2 + 1/a2 = -1
On cubing both sides, we get
(a2 + 1/a2)3 = (-1)3
? a6 + 1/a6 + 3a2 x 1/a2(a2 + 1/a2) = -1
? a6 + 1/a6 + 3 x (-1) = -1
Now, a6 + 1/a6 + 1 = 3
As, a12 + a6 + 1 can also be written as a6 + 1/a6 + 1
? a12 + a6 + 1 = 3
Angle between hands of a clock
When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock
=> degrees
Here H = 4, M = 15 and the minute hand is behind the hour hand.
Hence the angle
= 30[4-(15/5)]+15/2 = 30(1)+7.5 = 37.5 degrees
(kx22)/100 = 340 - 166.64 = 173.36
k = (173.36 x 100)/22
k = 788
For ticking 6 times, there are 5 intervals.
Each interval has time duration of 30/5 = 6 secs
At 12 o'clock, there are 11 intervals,
so total time for 11 intervals = 11 x 6 = 66 secs.
Let the three consecutive odd numbers be x, x+2, x+4
Then,
x + x + 2 + x + 4 = 93
=> 3x + 6 = 93
=> 3x = 87
=> x = 29 => 29, 31, 33 are three consecutive odd numbers.
Therefore, the middle number is 31.
On straight line means 180 degree angle.
180 = 11/2 min ? 30 hrs
180 = 11/2 m ? 30 × 3
180 = 11/2 m ? 90
(180 + 90) 2 = 11 m
m = 540/11 = 49 1/11 minutes.
Given the angles of a quadrilateral are in the ratio of 2:4:7:5
Let the angles of a quadrilateral are 2x, 4x, 7x, 5x
But we know that sum of the angles = 360 degrees.
=> 2x + 4x + 7x + 5x = 360
=> x = 20
Therfore, the smallest angle of the quadrilateral = 2x = 2x20 = 40 degrees.
One of the angle of the triangle = 2 x 40 = 80 degrees
The other angle is 180 - (40 + 80) = 60 degrees.
Hence the second largest angle of the triangle is 60 degrees.
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