We know that,
a3 + b3 + c3 - 3abc
= (a + b + c) 1/2 [(a - b) 2 + (b - c) 2 + (c - a) 2]
= (225 + 226 + 227) 1/2 [1 + 1 + 4]
= 678 x 3 = 2034
Given , X = ?3 + ?2
? 1/x = 1/(?3 + ?2)
Now Multiply and Divide by (?3 - ?2) in 1/x.
After multiply and divide, we will get
1/x = (1/(?3 + ?2)) X (?3 - ?2) /(?3 - ?2)
[rationalising]
? 1/x = ?3 - ?2/3 - 2
? x + 1/x = ?3 + ?2 + ?3 - ?2 = 2?3
Let, total number of workers be N .
Then number of women = N/3
Number of men = 2N/3
Number of women having children = 1/3 of 1/2 of N/3 = N/18
Number of men having children = 2/3 of 3/4 of 2N/3 = N/3
Number of workers having children = N/18 + N/3 = 7N/18
Number of workers having no children = N - 7N/18 = 11N/18
=11/18 of all workers
Given expression
= (2 - 1/3) (2 - 3/5) (2 - 5/7) ... (2 - 997/999)
= ((6 - 1)/3) ((10 - 3)/5) ((14 - 5)/7) ... ((1998 - 997)/999)
= 5/3 x 7/5 x 9/7 x ... x 1001/999
Multiply and solve by using the law of algebra,
= 5/3 x 7/5 x 9/7 x ... x 1001/999
= 1001/3
Since, a + b + c = 0
Then, a + b = - c .....(i)
a + c = - b ........(ii)
b + c = - a ......(iii)
Now,[(a + b)/c + (b + c)/a + (c + a)/b)] x [a/(b + c) + b/(c + a) + c/(a + b)]
Now, putting the value of a + b, b + c and c + a from Eqs (i), (ii) and (iii), we get
Given expression = [(-c)/c + (-a)/a + (-b)/b] [a/-a + b/-b + c/-c]
[(-1) + (-1) + (-1)] [(-1) + (-1) + (-1)]
= (-3) x (-3)
= 9
Let total score = N.
Then, the highest score = 3N/11.
Remainder = (N - 3N/11) = 8N/11
Next highest score = 3/11 of 8N/11 = 24N/121
According to the question,
(3N/11) - (24N/121) = 18
? 33N - 24N = 18 x 121
? 9N = 18 x 121
? N = (18 x 121)/9 = 242
Given expression
= 6 - [9 - {18 - (15 -12 - 9)}]
= 6 - [9 - {18 - (15 - 12 + 9)}]
= 6 - [9 - {18 - 12}]
= 6 - [9 - 6] = 6 - 3 = 3
Multiply the given in question.
The answer would be
? = 10.8 x 5.5 x 8.4 = 498.96
8648 - 7652 = ? x 40
996 = ? x 40 ? ? = 996/40 = 24.9
? = 683.46 - 227.39 - 341.85
= 683.46 - 569.24 = 114.22
Solution 1.
Let the question solved correctly by Mohan = X ;
and number of question solved wrongly by Mohan = 30 - X ;
According to the question,
3X - (30 - X) x 2 = 40
? 3x - 60 + 2x = 40
? 5x - 60 = 40
? 5x = 40 + 60 ? x = 100/5 = 20
? Mohan attempted 20 questions correctly .
Solution 2.
Let the question solved correctly by Mohan = X ;
and number of question solved wrongly by Mohan = Y ;
According to given question;
X + Y = 30 ; -----------i
3X - 2Y = 40 ;-------ii
Now multiply the first equation by 2;
we will get
2X + 2Y = 60 ;--------iii
After Add the equation ii and iii , we will get
3X - 2Y + 2X + 2Y = 40 + 60 ;
? 5X = 100 ;
? X = 20;
? Mohan attempted 20 questions correctly .
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.