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Home Aptitude Simplification Comments

  • Question
  • Solve [(999 + 588) 2 - (999 - 588) 2] / (999 x 588)


  • Options
  • A. 8
  • B. 3
  • C. 2
  • D. 4

  • Correct Answer


  • Explanation

    Given expression
    = [(a + b )2 - (a - b )2] / ab
    = 4ab/ab
    = 4
    where, a = 999, b = 588


  • Simplification problems


    Search Results


    • 1. 
      [0.5 x 0.5 x 0.5 + 0.2 x 0.2 x 0.2 + 0.3 x 0.3 x 0.3 - 3 x 0.5 x 0.3 x 0.2 ] / [0.5 x 0.5 + 0.2 x 0.2 + 0.3 x 0.3 - 0.5 x 0.2 - 0.2 x 0.3- 0.5 x 0.3] =?

    • Options
    • A. 1
    • B. 0.6
    • C. 0.4
    • D. 0.03
    • Discuss
    • 2. 
      [5 - [3/4 + {2 1/ 2 - (1/2 + 1/6 - 1/7)}]] / 2 =?

    • Options
    • A. 123/168
    • B. 223/168
    • C. 323/168
    • D. 423/168
    • Discuss
    • 3. 
      If a + b + c = 14 and a 2 + b 2 + c 2 = 96, then (ab + bc + ca) =?

    • Options
    • A. 51
    • B. 55
    • C. 50
    • D. 65
    • Discuss
    • 4. 
      If a + b + c = 0, then the value of [(a + b)/c + (b + c)/a + (c + a)/b] x [a/(b + c) + b/(c + a) + c/(a + b)] is?

    • Options
    • A. 9
    • B. 0
    • C. 8
    • D. -3
    • Discuss
    • 5. 
      If a, b and c are non-zero, a + 1/b = 1 and b + 1/c = 1, then the value of abc is?

    • Options
    • A. -3
    • B. 1
    • C. -1
    • D. 3
    • Discuss
    • 6. 
      Solve [(238 + 131) 2 + (238 - 131) 2] / (238 x 238 + 131 x 131)

    • Options
    • A. 4
    • B. 2
    • C. 8
    • D. 9
    • Discuss
    • 7. 
      If ? 2 = 1.4142, then the value of 7 / (4 + ? 2) is?

    • Options
    • A. 3.5858
    • B. 4.4142
    • C. 1.2929
    • D. 1.5858
    • Discuss
    • 8. 
      The value of (0.96) 3 - (0.1) 3/ [(0.96) 2 + (0.096) + 0.01] is?

    • Options
    • A. 0.86
    • B. 1.06
    • C. 0.95
    • D. 0.97
    • Discuss
    • 9. 
      3 2/ 3 + 2 3/ 4 + 1 1/ 2 =?

    • Options
    • A. 811/12
    • B. 1012/13
    • C. 711/12
    • D. 911/13
    • Discuss
    • 10. 
      (5568 ÷ 87) 1/3 + (72 x 2) 1/2 = (?) 1/2

    • Options
    • A. 256
    • B. 4
    • C. ?2
    • D. 16
    • Discuss


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