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  • Question
  • The taxi charges in a city contain fixed charges and additional charge per kilometer. The fixed charge is for a distance of up to 5 km and additional charge per kilometer thereafter. The charge for a distance of 10 km is ? 350 and for 25 km is ? 800. The charge for a distance of 30 km is


  • Options
  • A. ? 800
  • B. ? 750
  • C. ? 900
  • D. ? 950

  • Correct Answer
  • ? 950 

    Explanation

    let the fixed charges = ? p for first 5 km
    and the additional charges = ? q per km
    according to the question
    p + 5q = 350........... (1)
    p + 20q = 800...........(2)
    on subtracting Eq. 1 from Eq. 2 we get
    15q = 450
    q = 30
    On putting the value of q in Eq. (1) we get
    p = 200
    ? charge for a distance of 30 km = p + 25q
    = 200 + 30 x 25 = ? 950


  • More questions

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      0.0169 / 0.013=?

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    • A. .13
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    • 2. 
      Two posts are x meter apart and the height of one is double that of the other. If from the midpoint of the line joining their feet, an observer finds the angular elevations of their tops to be complementary, then the height (in meter) of the shorter post is :

    • Options
    • A. x 2 ?2
    • B. x 4
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    • D. x ?2
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    • 3. 
      If p/q =4/5, then the value of 4/7 + {(2q - p) / (2q + p)} is?

    • Options
    • A. 3 / 7
    • B. 34
    • C. 1
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    • 4. 
      What is 25% of 25% is equal to?

    • Options
    • A. 6.25
    • B. .625
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    • D. .000625
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    • 5. 
      The number .05 is hoe many percent of 20?

    • Options
    • A. 25
    • B. .025
    • C. .25
    • D. 2.5
    • Discuss
    • 6. Find the lowest common multiple of 24, 36 and 40.

    • Options
    • A. 120
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    • C. 360
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    • 7. 
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    • Options
    • A. 25/3
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      .025 in terms of term of rate per cent is?

    • Options
    • A. .25%
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    • 9. 
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    • Options
    • A. 2.5%
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    • 10. 
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    • Options
    • A. ? 1600
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    • C. ? 1800
    • D. ? 2800
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