Let the two number are a and b
According to the question
sum of squares of two numbers = 97
i.e.., a 2 + b 2 = 97 .....................(i)
and square of their difference = 25
i.e., (a - b) 2 = 25 .................(ii)
? a - b = 5...............(iii)
from Eq. (ii)
a2 + b2 - 2ab = 25
(a2 + b2) - 2ab = 25
Now put the value of a 2 + b 2 from Eq. (i)
? 97 - 2ab = 25
? 2ab = 72
? ab = 36.................(iv)
Now, we have
(a + b)2 = ( a2 + b2) + 2ab
Now put the value of a 2 + b 2 from Eq. (i) and ab from Eq. (iv)
(a + b)2 = 97 + 72 = 169
a + b = 13.............(v)
Now add the Eqs. (iii) and (v), we get
a - b + a + b = 5 +13
2a = 18
? a = 9
now put the value of a in Eq. (v)
a + b = 13
9 + b = 13
b = 13 - 9
b = 4
? Product of both the numbers = ab = 9 x 4 = 36
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
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