The only one even prime number is 2 and this is not in the form of 3k + 1.
Thus any prime number of the form 3k + 1 is an odd number.
This means 3k must be even number which implies that k must be even number also.
Let k = 2m.
Then a prime of the form 3k + 1 is of the form 3(2m) + 1 = 6m+1.
Every prime number of form 3k + 1 can be represented in the form 6m + 1 only, when k is even.
U ? A = {a, b, c, d, e, f} ? {a, b, c} = {a, b, c, d, e, f} = U
(U ? A)? = ?.
Sunil's income is less than Mukul's = [(10 / (100 + 10)] × 100 %
= ( 1000 / 110 )%
= 9.09 %
So, 39 is wrong.
So, 33 is wrong. It must be 35
∴ x = 7.
So, 40 is wrong.
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