Let the two numbers be 3N and 2N
According to the question.
10 + (3N +2N ) + (3N x 2N) = 162
? 6N2 + 5N - 246 = 0
? 6N2 + 41N - 36N - 246 = 0
? N(6N + 41 ) - 6(6N + 41) = 0
? (6N + 41 ) (N - 6) = 0
? N = 6 or -41/6 (But -ve value cannot be accepted )
? Smaller number = 2N = 2 x 6 = 12 .
xy = 96050 ...(i)
and xz = 95625 ...(ii)
and y - z = 1 ... (iii)
Dividing (i) by (ii) we get
y/z = 96050 / 95625
= 3842 / 3825
= 226 / 225 ... (iv)
Combining (iii) and (iv) we get z = 225.
Let the number be x.
? (x - 4)/6 = 9
? x = 58
Again (x - 3)/5 = (58 - 3)/5 = 11
Let the two-digit number be 10x + y
10x + y = 7(x + y)
? x = 2y ...(i)
10(x +2 ) + (y + 2) = 6(x + y + 4) + 4
or 10x + y + 22 = 6x + 6y + 28
? 4x - 5y = 6 ...(ii)
Solving equations (i) and (ii)
We get x = 4 and y = 2
Let 1/2 of the no. = 10x + y
and the no. = 10v + w
From the given conditions,
w= x and v = y-1
Thus the no. = 10 (y-1) + x
? 2(10x + y ) = 10 (y-1) + x
? 8y - 19x = 10 ...(i)
v + w = 7
? y-1 + x = 7
? x + y = 8
Solving equations (i) and (ii) , we get
x = 2 and y = 6
? From equations (A)
Number = 10 (y - 1) + x = 52.
Number of one digit pages from
1 to 9 = 9
Number of two digit pages from
10 to 99 = 90
Number of three digit pages from
100 to 200 = 101
? Total number of required figures
= 9 x 1 + 90 x 2 + 101 x 3 = 492
Let the original number be 10p + q.
So from question,
q = 2p + 1 ...(i)
and (10q + p) - (10p + q ) = (10p + q) - 1
? 9q - 9p = 10p + q -1
? 19p - 8q = 1...(ii)
Putting the value of (i) in equation (ii) we get
19p - 8(2p + 1) = 1
? 19p - 16p - 8 = 1
? 3p = 9
? p = 3
So, q = 2 x 3 + 1 = 7
? Original number = 10 x 3 + 7 = 37
Given Exp. ( 2 - 1/3) (2 - 3/5) (2 - 5/7) ...... (2 - 997/999)
= (5/3) x (7/5) x (9/7) x .......... x (1001/999)
= 1001/3.
Given Exp.= (1 - 1/3) (1 - 1/4) (1 - 1/5)...(1 - 1/n)
= (2/3) x (3/4) x (4/5) x ... x (n-1/n)
= 2/n.
To determine if a number is divisible by 99 it needs to be divisible by 9 and 11.
Divisible by 9 test. If sum of digits is divisible by 9 then the number is divisible by 9.
Divisible by 11 test. If sum of ODD positioned digits minus the sum of the EVEN positioned digits is divisible by 11 then the number is divisible by 11.
Clearly 114345 is divisible by 9 as well as 11. so,it is divisible by 99.
By hit and trial we find that 632 is divisible by 8. So, * must replaced by 3.
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