xy = 96050 ...(i)
and xz = 95625 ...(ii)
and y - z = 1 ... (iii)
Dividing (i) by (ii) we get
y/z = 96050 / 95625
= 3842 / 3825
= 226 / 225 ... (iv)
Combining (iii) and (iv) we get z = 225.
Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metres
? 2L x (9/25) = 36
? L = (25 x 36)/(2 x 9) = 50 metres.
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