The number is of the form (5x + 3 ) where x is an integer
? [(5x + 3)2] / 5 = ( 25x2 + 30x + 9) / 5
= 25x2/ 5 + 30x/5 + (5 +4)/5
? The remainder is 4.
Let the number be x, y, z
Then,
x + y = 45,
y + z = 55,
z + 3x = 30
Now, y = (45 - x) and
z = 55 - y
? z = 55 - (45 - x ) = 10 + x
? 10 + x + 3x = 90
? x = 20
So, third number = z
= 10 + x = 30
Let the numbers be x and y ,
Then, 2x + 3y = 18 ....(i),
3x + 2y = 17 ....(ii)
Solving, we get x =3 , y= 4
? Largest number = 4
Let the number be a and b .
Then a2 + b2 = 68 ....(i)
and (a - b)2 = 36
Now, (a - b)2 = 36 ....(ii)
? a2 + b2 - 2ab = 36
? 68 - 2ab = 36
? 2ab = 32
? ab = 16 .
Let the required fraction be p/q.
Then, (p +1) / (q +1) = 4
? p - 4q= 3 ....(i)
And, (p - 1) / (q -1) = 7
? p - 7q = -6 ....(ii)
Solving these equation we get p = 15, q=3
Let unit digit = x and ten's digit = y
3(x + y)= 10y + x .....(i)
10y + x + 45 = 10x + y ....(ii)
2x - 7y = 0.9x -9y = 45
or x - y = 5 .... (iii)
Solving these equations, we get
x=7, y=2
? Required number = 27
According to the question
Divisor = 2/3 x dividend
and Divisor = 2 x remainder
or 2/3 x dividend = 2 x 5
? Dividend = 2 x 5 x 3 / 2 = 15
Number of one digit pages from
1 to 9 = 9
Number of two digit pages from
10 to 99 = 90
Number of three digit pages from
100 to 200 = 101
? Total number of required figures
= 9 x 1 + 90 x 2 + 101 x 3 = 492
Let 1/2 of the no. = 10x + y
and the no. = 10v + w
From the given conditions,
w= x and v = y-1
Thus the no. = 10 (y-1) + x
? 2(10x + y ) = 10 (y-1) + x
? 8y - 19x = 10 ...(i)
v + w = 7
? y-1 + x = 7
? x + y = 8
Solving equations (i) and (ii) , we get
x = 2 and y = 6
? From equations (A)
Number = 10 (y - 1) + x = 52.
Let the two-digit number be 10x + y
10x + y = 7(x + y)
? x = 2y ...(i)
10(x +2 ) + (y + 2) = 6(x + y + 4) + 4
or 10x + y + 22 = 6x + 6y + 28
? 4x - 5y = 6 ...(ii)
Solving equations (i) and (ii)
We get x = 4 and y = 2
Let the number be x.
? (x - 4)/6 = 9
? x = 58
Again (x - 3)/5 = (58 - 3)/5 = 11
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