Let the number be N.
According to the question,
N - (N x 3/4) =163
? N/4 =163
? N=652
Given Exp. = 6/7 + [(y - x)/(y + x)]
= 6/7 + [1 - (x/y) / 1 + (x/y)]
= 6/7 + [1 - (3/4)] / [1 + (3/4)]
= 6/7 + 1/7 =1.
Let 62976/N = 123
Then N = 62976 / 123 = 512.
Let 4050/?N = 450
Then ?N = 4050/450 = 9
? N = (9 x 9) = 81.
Let √N/19 = 4
Then √N = 19 x 4 = 76
∴ N = 76 x 76 = 5776.
Let the number be N.
According to the question,
(N x 3)/2 - N / (3/2) = 10
? 3N/2 - 2N/3 = 10
? (9N - 4N) / 6 = 10
? 5N / 6 = 10
? N = (10 x 6)/5 = 12
Let the positive number be N.
According to the question,
N + 10 = 200 / N
? N2 + 10N = 200
? N2 +10N - 200 =0
? (N - 10)(N + 20) = 0
? N = 10 & N= -20
But N not equal to -20 since N is a positive number
So, the required number is 10
Total share given by the person = (1/4) + (1/2) + (1/5)
= (5 + 10 + 4) / 20
=19/20
Let the number be a and b Then
a + b = 10 ..........(i)
ab = 20 ........(ii)
Sum of reciprocal = 1/a + 1/b
= (a + b) / ab
= 10/20
= 1/2
the number of pieces of chocolate left with manju =1- [(1/4) + (1/3) + (1/6)]
= 1 - [ (3 + 4 + 2)/12)
= 1 - (9/12)
= 3/12
Hence number of piece of chocolate left with in manju is 3
Factors of composite number = (P1 +1)(P2+1)(P3+1)......(Pn+1).
Where P1,P2,P3... Pn are the powers of respective prime factors.
So,
120= 23 x 31 x 51
Factors=(3+1)(1+1)(1+1)=16.
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