Let √N/19 = 4
Then √N = 19 x 4 = 76
∴ N = 76 x 76 = 5776.
Let the number be N.
According to the question,
(N x 3)/2 - N / (3/2) = 10
? 3N/2 - 2N/3 = 10
? (9N - 4N) / 6 = 10
? 5N / 6 = 10
? N = (10 x 6)/5 = 12
The number of pieces of chocolate left with Manju
= 1- [(1/4) + (1/3) + (1/6)
= 1 - (3 + 4 + 2)/12
= 1 - 9/12 = (12 - 9) / 12
= 3/12
Total share given by a person
= (1/4) + (1/2) + (1/5)
= (5 + 10 + 4)/20
= 19/20
Let the number be N.
According to the question,
? 5N = 2N2 - 3
? 2N2 - 5N - 3 = 0
? (N - 3) ( 2N + 1 ) = 0
N = 3 and N = -1/2
Thus, the required number is 3.
Here, M + N = 10 and MN = 20
According to the question,
(1/M) + (1/N) = (M + N) / MN = 10/20 = 1/2
Let 4050/?N = 450
Then ?N = 4050/450 = 9
? N = (9 x 9) = 81.
Let 62976/N = 123
Then N = 62976 / 123 = 512.
Given Exp. = 6/7 + [(y - x)/(y + x)]
= 6/7 + [1 - (x/y) / 1 + (x/y)]
= 6/7 + [1 - (3/4)] / [1 + (3/4)]
= 6/7 + 1/7 =1.
Let the number be N.
According to the question,
N - (N x 3/4) =163
? N/4 =163
? N=652
Let the positive number be N.
According to the question,
N + 10 = 200 / N
? N2 + 10N = 200
? N2 +10N - 200 =0
? (N - 10)(N + 20) = 0
? N = 10 & N= -20
But N not equal to -20 since N is a positive number
So, the required number is 10
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