If the three- fourth of number is subtracted from the number, the value so obtained is 163. What is that number?

Let the two consecutive numbers are N and N+2

According to the question
N (N + 2) = 19043
? N² + 2N - 19043 = 0
? N² + 139N - 137N - 19043= 0
? N( N + 139) - 137 ( N - 137 ) = 0
? N( N + 139) ( N - 137) = 0
? N = 137 and N = - 139
? N = 137

Let the number be N
According to the question N x ( N x 3)/4 = 10800
? 3N² / 4 = 10800
? N² = (10800 x 4) / 3= 14400
N = ?14400 = 120

Let quotient = Q and remainder = R
Then, Divisor = 12 Q =5 R
Now, R = 48
? 12Q = 5 x 48
? Q = 20

Dividend = Divisor x Quotient + Remainder
? dividend = ( 20 x 240 + 48 )
= 4848

Required number is 2 x 4 x 6 = 48.

Let 10/11 = 110/N,
Then, 10N = 11 x 110
? N = (11 x 110) /10 = 121.

Let the positive number be N.
According to the question,
N + 10 = 200/N
? N² + 10N = 200
? N² + 10N - 200 = 0
? ( N - 10) ( N + 20) = 0
&ythere4; N = 10 and N = -20
But N ? -20, since N is a positive number.
So, the required number is 10.

Here, M + N = 10 and MN = 20
According to the question,
(1/M) + (1/N) = (M + N) / MN = 10/20 = 1/2

Let the number be N.
According to the question,
? 5N = 2N² - 3
? 2N² - 5N - 3 = 0
? (N - 3) ( 2N + 1 ) = 0
N = 3 and N = -1/2
Thus, the required number is 3.

Total share given by a person
= (1/4) + (1/2) + (1/5)
= (5 + 10 + 4)/20
= 19/20

The number of pieces of chocolate left with Manju
= 1- [(1/4) + (1/3) + (1/6)
= 1 - (3 + 4 + 2)/12
= 1 - 9/12 = (12 - 9) / 12
= 3/12