Let 80/y = y/20
Then, y 2 = 80 x 20 = 1600
? y = ?1600 = 40.
? Five dozen = 5 x 12 = 60
? No of toys can be kept in 1 box = 60
? No of toys can be kept in 98 boxes = 60 x 98 = 5880
? 29400 toys can be lifted by = 29400 / 5880 = 5 tempos
? Cost of 6 dozen chairs = 6 x 12 x214 = Rs. 15408
And cost of 4 dozen tables = 4 x 12 x 937 = Rs. 44976
? Total cost =15408 + 44976
= Rs. 60384
= Rs. 60000 (Approximately)
?Weight of 13 m long rod = 23.4 kg
? Weight of 1 m long rod = 23.4 / 13 kg
? Weight of 6 m long rod = 23.4 x 6 / 13
= 10.8 kg
No. of pieces = Total length / Length of each piece
= 192/3.2
= 60
Dividing numerator as well as denominator by b, we get
Given Exp. = (3a + 2b) / (3a - 2b) = (3a/b + 2) / (3a/b - 2)
= [ (3 x 4) / 3 + 2 ] / [ (3 x 4)/3 - 2 ]
= (4 + 2) / (4 - 2)
= 3
Let (y/21) x (y/189) = 1
Then , y2 = 21 x 189 = 21 x 21 x 9
? y = (21 x 3) = 63 .
On dividing 13601 by 86, we get 29 as remainder
? Required number to be subtracted = 29.
Let 392/?x = 28
Then ?x = 392/28 =14
? x = 142 = 196
First four prime numbers are 2,3,5,7,
Their sum = (2 + 3 + 5 + 7) = 17.
The first prime number is 2.
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