When a 192 meters long rod is cut down into small pieces of length 3.2 meters each. Then how many pieces are available?

Dividing numerator as well as denominator by b, we get
Given Exp. = (3a + 2b) / (3a - 2b) = (3a/b + 2) / (3a/b - 2)
= [ (3 x 4) / 3 + 2 ] / [ (3 x 4)/3 - 2 ]
= (4 + 2) / (4 - 2)
= 3

? ?3ⁿ = 81
? 3^n/2= 3⁴
? n/2 = 4
? n = 8.

Given Exp. = 4 / 7 + {(2q - p) / (2q + p)}
Dividing numerator as well as denominator by q,
Exp = 4/7 + {2-p/q) / (2 + p/q)}
= 4/7 + {(2 - 4/5) / (2 + 4/5)}
= 4/7 + 6/14
= 4/7 + 3/7
=7/7
=1.

√ N / 196 = 72 / 56 =9/7
Then, N/196 = 9/7 x 9/7 = 81 / 49
So, N = (81 x 196) / 49 = 324.

Let 24 / 18 = N / 6
Then, 18N = 24 x 6
? N = ( 24 x 6) / 18
= 8.

?Weight of 13 m long rod = 23.4 kg
? Weight of 1 m long rod = 23.4 / 13 kg
? Weight of 6 m long rod = 23.4 x 6 / 13
= 10.8 kg

? Cost of 6 dozen chairs = 6 x 12 x214 = Rs. 15408
And cost of 4 dozen tables = 4 x 12 x 937 = Rs. 44976
? Total cost =15408 + 44976
= Rs. 60384
= Rs. 60000 (Approximately)

? Five dozen = 5 x 12 = 60
? No of toys can be kept in 1 box = 60
? No of toys can be kept in 98 boxes = 60 x 98 = 5880
? 29400 toys can be lifted by = 29400 / 5880 = 5 tempos

Let 80/y = y/20
Then, y ² = 80 x 20 = 1600
? y = ?1600 = 40.

Let (y/21) x (y/189) = 1
Then , y² = 21 x 189 = 21 x 21 x 9
? y = (21 x 3) = 63 .