Let the three consecutive numbers be x, x+1 and x+2 respectively
? Diff between first and third numbers = (x + 2) - x
= 2
Let the number be N.
Then (N/2)2 - N = 48
? N2/4 - N = 48
?N2 - 4N-192= 0
? (N-16) (N+12) = 0
? N = 16
? The square root of the number is 4.
Let the antecedent be N.
Then, N/24 = 2/3
? N = (24 x 2) / 3
= 16
Let the number be N and (50 - N)
Then, 1/N + 1/(50-N) = 1/12
? (50 - N + N) / {N(50 - N)} = 1/12
? N2 - 50N + 600 = 0
? N = 30 or 20
? the number are 20, 30
Let the required number be N,
Then, N/6 = N - 40
? N + 240 = 6N
? N = 48.
Let the requirement odd integers be N, N +2 and N + 4
Then, N + (N + 2) + (N + 4) = 57
? 3N = 51
? N = 17
? The integers are 17, 19, 21.
Let the number be N.
Then, N - N/3 = 48
2N/3 = 48.
Here neither the remainder nor the dividend nor the second number is given. So, can't be determined.
Let the number be N
? (1/2 + 1/3 + 1/4)N = {(6 +4 +3) x N } / 12
= 13N / 12
According to the question,
13N/12 - N = 4
? N = 48
Let first and second numbers are p & q.
p/5 = 5q/8
? p/q = 25/8 ...(i)
p + 35 = 4q
or 25q/8 + 35= 4q
? q = 40.
469157 x 9999 = 469157 x (10000-1)
= 4691570000 - 469157
= 4691100843.
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