What will be the output of the program? public class WaitTest { public static void main(String [] args) { System.out.print("1 "); synchronized(args) { System.out.print("2 "); try { args.wait(); /* Line 11 */ } catch(InterruptedException e){ } } System.out.print("3 "); } }

It fails to compile because the IllegalMonitorStateException of wait() is not dealt with in line 11.
1 2 3
1 3
1 2

Correct Answer: 1 2

Explanation:

1 and 2 will be printed, but there will be no return from the wait call because no other thread will notify the main thread, so 3 will never be printed. The program is essentially frozen at line 11.

A is incorrect; IllegalMonitorStateException is an unchecked exception so it doesn't have to be dealt with explicitly.

B and C are incorrect; 3 will never be printed, since this program will never terminate because it will wait forever.

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What will be the output of the program? public class WaitTest { public static void main(String [] args) { System.out.print("1 "); synchronized(args) { System.out.print("2 "); try { args.wait(); /* Line 11 */ } catch(InterruptedException e){ } } System.out.print("3 "); } }

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