£-1F(s) = f(t)
£[a f1(t) + bf2(t)] = aF1(s) + bF2(s)
where
£[f(t - T)] = e-sT F(s)
£[e-at f(t)] = F(s + a)
Initial value theorem
Final value theroem
Convolution Integral
where t is dummy variable for t.
Apply KVL to mesh 2
-2 + Vy + 1 = 0
? Vy = 1
Apply KVL to mesh 1
? -8 + Vx + 2 = 0
? Vx = 6 V
Apply KVL to mesh 3
-1 + Vz -2 = 0
? Vz = 3 V.
Where ? = conductivity
Given -> ? = 0.13 m2/v-s = 0.13 x 104 cm2/V sec
P = 2.25 x 1015/cm3
We have, ? ni = 1.5 x 1010
Also n.p. =
? n = /p
= (1.6 x 10-19 x 0.13 x 104 x 2.25 x 1015) x
= (0.468) (4.5 x 1015)
? = 2.106 x 1015 ?/cm
J = ?E
? Current density = 2.106 x 1015 x 3.620 x 10-19
= 7.6237 x 10-4 A/m2.
(A + B + C) (A + B + C) (A + B + C).
F1 > F2 > F3
j = light intensity = constant
Photocurrent Vs Anode voltage with frequency and incident light as a parameter.
The light intensity is constant.
Then ROC for x1(n) + x2(n)
R1 ? R2 (R1 < R2)
Then ROC for x1(n) + x2(n)
R1 ? R2(R1 < R2)
Include unity circle and exterior of circle hence x(z) will be stable, causal.
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