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From II, we have: E > B > D.
Combining the above two, we get :E > B > D > A > C or E > B > D >C > A.
Thus, E is the tallest.
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From II, we find that one-third of 15 i.e. 5 speakers gave 2 speeches each, while each of the remaining 10 speakers delivered only one speech.
So, total number of speeches delivered = (5 x 2 + 10 x 1) = 20.
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From II, we conclude that M and N are the children of S. Also, R is the daughter-in-law of S and sister-in-law of M. So, R is N's wife and thus, N is M's brother. Hence, M is either brother or sister of N.
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According to II, Hitesh's mother reached his house day after Monday i.e. on Tuesday.
Thus, Hitesh visited zoo two days before Tuesday i.e. on Sunday.
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The time of visit of no department is mentioned in II, which is, therefore, insufficient.
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