Draw a table with Student, Subject and Sport.
P studies in Class II.
Q likes black.
R does not study in Class VI.
S likes pink and studies in Class I.
M likes blue.
Q likes black and does not study in Class IV or V.
The one who studies in Class IV does not like green.
M likes blue and does not study in Class IV.
The one who likes yellow studies in Class VI.
R does not study in Class VI.
Based on the above information, the classification of the group is as follow in the table.
Then, 3x = 15 or x = 5.
So, number of girls participating in sports = 2x = 10.
Number of students not participating in sports = 60 - (15 + 10) = 35.
Let number of boys not participating in sports be y.
Then, number of girls not participating in sports = (35 -y).
Therefore (35 - y) = y + 5 ⟺ 2y ⟺ 30 ⟺ y = 15.
So, number of girls not participating in sports = (35 - 15) = 20.
Hence, total number of girls in the class = (10 + 20) = 30.
Draw a table with Student, Subject and Sport.
P studies in Class II.
Q likes black.
R does not study in Class VI.
S likes pink and studies in Class I.
M likes blue.
Q likes black and does not study in Class IV or V.
The one who studies in Class IV does not like green.
M likes blue and does not study in Class IV.
The one who likes yellow studies in Class VI.
R does not study in Class VI.
Based on the above information, the classification of the group is as follow in the table.
Draw a table with Student, Subject and Sport.
P studies in Class II.
Q likes black.
R does not study in Class VI.
S likes pink and studies in Class I.
M likes blue.
Q likes black and does not study in Class IV or V.
The one who studies in Class IV does not like green.
M likes blue and does not study in Class IV.
The one who likes yellow studies in Class VI.
R does not study in Class VI.
Based on the above information, the classification of the group is as follow in the table.
Some sparrows are crow + Some crows are pigeons = I + I = No conclusion Hence III does not follow. Some crows are pigeons (I) ? conversion ? Some pigeons are crows (I) Now, all parrots are pigeons + Some pigeons are crows = A + I = No conclusion Hence II does not follow. Nor does IV follow. However conversion II from an I-E complementary pair with IV, Hence either I or IV follows. Some sparrows are crows(I) ? conversion ? Some crows are sparrows + All sparrows are koels ? conversion ? Some koels are crows (I). Hence I.
Both assumptions are negative and hence, invalid.
'Leap' is the movement of rabbit ; 'Frisk' is the movement of 'Lamb' and 'Trop' is movement of 'Donkey'.
So, 550 is wrong and must be replaced by (320 x 2) i.e. 640.
Only I is implicit. Why does the company need to issue such instruction? It must be assuming I. The motive behind the instruction may be to ensure convenience in keeping the records regarding transaction of the company. Hence, II is not implicit.
From the information given in the question, we can have the following table:
Eight people, viz A, B, C, D, E, F, G and H are sitting in a straight line facing North. Each of them has passed a recruitment exam and must join the office in different months, viz January, February, March, April, May, June, July and August but not necessarily in the same order.
Hence , H join the office in February month .
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