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- Question
If a clock takes seven seconds to strike seven, how long will it take to strike ten?
Options- A. 7 seconds
- B. 9 seconds
- C. 10 seconds
- D. None of these
- Correct Answer
- None of these
Explanation
Arithmetic Reasoning problems
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- 1. A group of 1200 persons consisting of captains and soldiers is travelling in a train. For every 15 soldiers there is one captain. The number of captains in the group is
Options- A. 85
- B. 80
- C. 75
- D. 70 Discuss
Correct Answer: 75
Explanation:
Clearly, out of every 16 persons, there is one captain. So, number of captains (1200/16) = 75.- 2. In a class, 3/5 of the students are girls and rest are boys. If 2/9 of the girls and 1/4 of the boys are absent, what part of the total number of students is present?
Options- A. 17/25
- B. 18/49
- C. 23/30
- D. 23/36 Discuss
Correct Answer: 23/30
Explanation:
- 3. A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what time will he first touch a flag at 120 feet from the ground?
Options- A. 4 p.m.
- B. 5 p.m.
- C. 6 p.m.
- D. None of these Discuss
Correct Answer: 6 p.m.
Explanation:
Net ascent of the monkey in 1 hour = (30 - 20) feet = 10 feet.So, the monkey ascends 90 feet in 9 hours i.e. till 5 p.m.
Clearly, in the next 1 hour i.e. till 6 p.m. the monkey ascends remaining 30 feet to touch the flag.
- 4. At the end of a business conference the ten people present all shake hands with each other once. How many handshakes will there be altogether?
Options- A. 20
- B. 45
- C. 55
- D. 90 Discuss
Correct Answer: 45
Explanation:
Clearly, total number of handshakes = (9+ 8 + 7 + 6 + 5 + 4 + 3 + 2+1) = 45.- 5. A number consists of two digits whose sum is 11. If 27 is added to the number, then the digits change their places. What is the number?
Options- A. 47
- B. 65
- C. 83
- D. 92 Discuss
Correct Answer: 47
Explanation:
Let the ten's digit be x. Then, unit's digit = (11 - x).So, number = 10x + (11 - x) = 9x + 11.
Therefore (9x + 11) + 27 = 10 (11 - x) + x ⟺ 9x + 38 = 110 - 9x ⟺ 18x = 72 ⟺ x = 4.
Thus, ten's digit = 4 and unit's digit = 7.
Hence, required number = 47.
- 6. Aruna cut a cake into two halves and cuts one half into smaller pieces of equal size. Each of the small pieces is twenty grams in weight. If she has seven pieces of the cake in all with her, how heavy was the original cake?
Options- A. 120 grams
- B. 140 grams
- C. 240 grams
- D. 280 grams
- E. None of these Discuss
Correct Answer: 240 grams
Explanation:
The seven pieces consist of 6 smaller equal pieces and one half cake piece.Weight of each small piece = 20 g.
So, total weight of the cake = [2 x (20 x6)]g= 240 g.
- 7. An enterprising businessman earns an income of Re. 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. One the 10th day of business, his income is
Options- A. Rs. 29
- B. Rs. 210
- C. Rs. 10
- D. Rs. 102 Discuss
Correct Answer: Rs. 29
Explanation:
Income on the first day = Re. 1.Income on the 2nd day = Rs. (1x2) = Rs. 21.
Income on the 3rd day = Rs. (21 x 2) = Rs. 22 and so on. Thus, Income on the rath day = Rs. 2n-1.
Therefore Income on the 10th day = Rs. 29.
- 8. In a caravan, in addition to 50 hens, there are 45 goats and 8 camels with some keepers. If the total number of feet be 224 more than the number of heads in the caravan, the number of keepers is
Options- A. 5
- B. 8
- C. 10
- D. 15 Discuss
Correct Answer: 15
Explanation:
Let number of keepers be x. Then,Total number of feet = 2 x 50 + 4 x 45 + 4 x 8 + 2x = 2x + 312.
Total number of heads = 50 + 45 + 8 + x= 103 + x.
Therefore (2x + 312) = (103 + x) + 224 or x = 15.
- 9. I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If I keep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute?
Options- A. 25
- B. 37
- C. 54
- D. 65 Discuss
Correct Answer: 25
Explanation:
Clearly, the required number would be such that it leaves a remainder of 1 when divided by 2, 3 or 4 and no remainder when divided by 5. Such a number is 25.- 10. If a 1 mm thick paper is folded so that the area is halved at every fold, then what would be the thickness of the pile after 50 folds?
Options- A. 100 km
- B. 1000 km
- C. 1 million km
- D. 1 billion km Discuss
Correct Answer: 1 billion km
Explanation:
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