3rd term = (2nd term) x 3 - 4 = 26 x 3 - 4 = 74.
4th term = (3th term) x 3 - 4 = 74 x 3 - 4 = 218.
5th term = (4th term) x 3 - 4 = 218 x 3 - 4 = 650.
∴ 5th term must be 650 instead of 654.
3rd term = (2nd term) x 2 + 2 = 16 x 2 + 2 = 34.
4th term = (3th term) x 3 + 3 = 34 x 3 + 3 = 105.
5th term = (4th term) x 4 + 4 = 105 x 4 + 4 = 424
6th term = (5th term) x 5 + 5 = 424 x 5 + 5 = 2125
∴ 6th term should 2125 instead of 2124.
So, 135 is wrong.
So, 39 is wrong.
So, 200 is wrong.
2nd term = (1st term) x 2 = 6 x 2 = 12
4th term = (3rd term) x 2 = 48 x 2 = 96.
6th term = (5th term) x 2 = 384 x 2 =768.
∴ 4th term should be 96 instead of 100.
Clearly, 92 is wrong.
So, 27 is wrong.
Last digit will be multiplication of 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9.
It includes 5 & 2.
So, 5 x 2=10,
0 will be the last digit.
By checking options
91-19=72
Or
Let the number be xy
So 10x + y = 10 ..... (i)
When the number is reversed the new number is yx
So (10y + 10 ) - ( 10x +y ) = 72 ....(ii)
From Eqs. (i) & (ii)
x = 1 and y =9
?number = 19
Place value of 5 in 65231 = 5 x 1000
= 5000
Face value = 5
required product = 5000 x 5 = 25000
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