Functions can be declared to return a reference type. There are reasons to make such a declaration/Which of the following reasons are correct?

1. The information being returned is a large enough object that returning a reference is more efficient than returning a copy.
2. The type of the function must be a R-value.

#include<iostream.h> 
class CuriousTabTeam
{
    int x, y; 
    public:
    CuriousTabTeam(int xx)
    {
        x = ++xx;
    }
    void Display()
    {
        cout<< --x << " ";
    }
};
int main()
{
    CuriousTabTeam objBT(45);
    objBT.Display();
    int *p = (int*)&objBT;
    *p = 23;
    objBT.Display();
    return 0; 
}

1. All function calls are resolved at compile-time in Procedure Oriented Programming.
2. All function calls are resolved at compile-time in OOPS.

#include<iostream.h> 
class CuriousTab
{
    int x, y; 
    public:
    CuriousTab(int xx = 10, int yy = 20 )
    {
        x = xx; 
        y = yy;
    }
    void Display()
    {
        cout<< x << " " << y << endl;
    } 
    ~CuriousTab()
    { } 
};
int main()
{
    CuriousTab objCuriousTab; 
    objCuriousTab.Display(); 
    return 0;
}

1. Once a reference variable has been defined to refer to a particular variable it can refer to any other variable.
2. A reference is not a constant pointer.