X = 2.57
X = (X + 0.06) * 10
I = TRUNC (X)
X = I
X = X / 10.0
The final value of X would be
RAL instruction
IF (JCOKE - 3 * LPEPSI) 5, 6, 7
5 JCOKE = JCOKE + 5
6 JCOKE = JCOKE + 8
7 JCOKE = JCOKE + 11
The value of JCOKE after the execution of above statement will be
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.