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- Question
At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party?
Options- A. 60
- B. 65
- C. 90
- D. None of these
- Correct Answer
- 60
Explanation
Arithmetic Reasoning problems
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- 1. In a class, 20% of the members own only two cars each, 40% of the remaining own three cars each and the remaining members own only one car each. Which of the following statements is definitely true from the given statements?
Options- A. Only 20% of the total members own three cars each.
- B. 48% of the total members own only one car each.
- C. 60% of the total members own at least two cars each.
- D. 80% of the total members own at least one car.
- E. None of these Discuss
Correct Answer: 48% of the total members own only one car each.
Explanation:
Let total number of members be 100,Then, number of members owning only 2 cars = 20.
Number of members owning 3 cars = 40% of 80 = 32.
Number of members owning only 1 car = 100 - (20 + 32) = 48.
Thus, 48% of the total members own one car each.
- 2. The number of boys in a class is three times the number of girls. Which one of the following numbers cannot represent the total number of children in the class?
Options- A. 48
- B. 44
- C. 42
- D. 40 Discuss
Correct Answer: 42
Explanation:
Let number of girls = x and number of boys = 3x.Then, 3x + x = 4x = total number of students.
Thus, to find exact value of x, the total number of students must be divisible by 4.
- 3. In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is
Options- A. 20 m
- B. 22 m
- C. 24 m
- D. 26 m Discuss
Correct Answer: 24 m
Explanation:
Each row contains 12 plants.There are 11 gapes between the two corner trees (11 x 2) metres and 1 metre on each side is left.
Therefore Length = (22 + 2) m = 24 m.
- 4. Three friends had dinner at a restaurant. When the bill was received, Amita paid 2/3 as much as Veena paid and Veena paid 1/2 as much as Tanya paid. What faction of the bill did Veena pay?
Options- A. 1/3
- B. 3/11
- C. 12/13
- D. 5/8 Discuss
Correct Answer: 3/11
Explanation:
- 5. A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have?
Options- A. 22
- B. 23
- C. 25
- D. 35 Discuss
Correct Answer: 25
Explanation:
Clearly, we have :B-3 = E ...(i)
B + 3 = D ...(ii)
A+B = D + E+10 ...(iii)
B = C + 2 ...(iv)
A+B + C + D + E= 133 ...(v)
From (i) and (ii), we have : 2 B = D + E ...(vi)
From (iii) and (vi), we have : A = B + 10 ...(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B - 2) + 2B = 133 ⟺ 5B = 125 ⟺ B = 25.
- 6. The total number of digits used in numbering the pages of a book having 366 pages is
Options- A. 732
- B. 990
- C. 1098
- D. 1305 Discuss
Correct Answer: 990
Explanation:
Total number of digits= (No. of digits in 1- digit page nos. + No. of digits in 2-digit page nos. + No. of digits in 3- digit page nos.)
= (1 x 9 + 2 x 90 + 3 x 267) = (9 + 180 + 801) = 990.
- 7. Five bells begin to toll together and toll respectively at intervals of 6, 5, 7, 10 and 12 seconds. How many times will they toll together in one hour excluding the one at the start?
Options- A. 7 times
- B. 8 times
- C. 9 times
- D. 11 times Discuss
Correct Answer: 8 times
Explanation:
L.C.M. of 6, 5, 7, 10 and 12 is 420.So, the bells will toll together after every 420 seconds i.e. 7 minutes.
Now, 7 x 8 = 56 and 7 x 9 = 63.
Thus, in 1-hour (or 60 minutes), the bells will toll together 8 times, excluding the one at the start.
- 8. In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score?
Options- A. 62
- B. 45
- C. 28
- D. 20 Discuss
Correct Answer: 20
Explanation:
Total runs scored = (36 x 5) = 180.Let the runs scored by E be x.
Then, runs scored by D = x + 5; runs scored by A = x + 8;
runs scored by B = x + x + 5 = 2x + 5;
runs scored by C = (107 - B) = 107 - (2x + 5) = 102 - 2x.
So, total runs = (x + 8) + (2x + 5) + (102 - 2x) + (x + 5) + x = 3x + 120.
Therefore 3x + 120 =180 ⟺ 3X = 60 ⟺ x = 20.
- 9. In a family, each daughter has the same number of brothers as she has sisters and each son has twice as many sisters as he has brothers. How many sons are there in the family?
Options- A. 2
- B. 3
- C. 4
- D. 5 Discuss
Correct Answer: 3
Explanation:
Let d and s represent the number of daughters and sons respectively.Then, we have :
d - 1 = s and 2 (s - 1) = d.
Solving these two equations, we get: d = 4, s = 3.
- 10. A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's age is
Options- A. 23 years
- B. 34 years
- C. 45 years
- D. None of these Discuss
Correct Answer: 45 years
Explanation:
Let x and y be the ten's and unit's digits respectively of the numeral denoting the woman's age.Then, woman's age = (10X + y) years; husband's age = (10y + x) years.
Therefore (10y + x)- (10X + y) = (1/11) (10y + x + 10x + y)
⟺ (9y-9x) = (1/11)(11y + 11x) = (x + y) ⟺ 10x = 8y ⟺ x = (4/5)y
Clearly, y should be a single-digit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, woman's age = 10x + y = 45 years.
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