3 |
20 |
29 |
34 |
47 |
100 |
13 |
102 |
13 |
102 |
Then, n(S) = 52C2 = | (52 x 51) | = 1326. |
(2 x 1) |
Let E = event of getting 1 spade and 1 heart.
∴ n(E) | = number of ways of choosing 1 spade out of 13 and 1 heart out of 13 |
= (13C1 x 13C1) | |
= (13 x 13) | |
= 169. |
∴ P(E) = | n(E) | = | 169 | = | 13 | . |
n(S) | 1326 | 102 |
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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