1 |
22 |
3 |
22 |
2 |
91 |
2 |
77 |
2 |
91 |
Then, n(S) | = number of ways of drawing 3 balls out of 15 | |||
= 15C3 | ||||
|
||||
= 455. |
Let E = event of getting all the 3 red balls.
∴ n(E) = 5C3 = 5C2 = | (5 x 4) | = 10. |
(2 x 1) |
∴ P(E) = | n(E) | = | 10 | = | 2 | . |
n(S) | 455 | 91 |
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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