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- Question
A runs 1⅔ times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
Options- A. 200 m
- B. 300 m
- C. 270 m
- D. 160 m
- Correct Answer
- 200 m
ExplanationRatio of the speeds of A and B = 5 : 1 = 5 : 3. 3 Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
80 m will be gained by A in race of ❨ 5 x 80 ❩m = 200 m. 2 ∴ Winning post is 200 m away from the starting point.
Races and Games problems
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- 1. In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:
Options- A. 5.4 m
- B. 4.5 m
- C. 5 m
- D. 6 m Discuss
Correct Answer: 6 m
Explanation:
A : B = 100 : 90.A : C = 100 : 87.
B = B x A = 90 x 100 = 30 . C A C 100 87 29 When B runs 30 m, C runs 29 m.
When B runs 180 m, C runs ❨ 29 x 180 ❩m = 174 m. 30 ∴ B beats C by (180 - 174) m = 6 m.
- 2. At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90?
Options- A. 30 points
- B. 20 points
- C. 10 points
- D. 12 points Discuss
Correct Answer: 10 points
Explanation:
A : B = 60 : 45.A : C = 60 : 40.
∴ B = ❨ B x A ❩ = ❨ 45 x 60 ❩ = 45 = 90 = 90 : 80. C A C 60 40 40 80 ∴ B can give C 10 points in a game of 90.
- 3. A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:
Options- A. 5.15 kmph
- B. 4.14 kmph
- C. 4.25 kmph
- D. 4.4 kmph Discuss
Correct Answer: 4.14 kmph
Explanation:
A's speed = ❨ 5 x 5 ❩m/sec = 25 m/sec. 18 18 Time taken by A to cover 100 m = ❨ 100 x 18 ❩sec = 72 sec. 25 ∴ Time taken by B to cover 92 m = (72 + 8) = 80 sec.
∴ B's speed = ❨ 92 x 18 ❩kmph = 4.14 kmph. 80 5 - 4. In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:
Options- A. 60 m
- B. 40 m
- C. 20 m
- D. 10 m Discuss
Correct Answer: 20 m
Explanation:
To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers ❨ 4 x 360 ❩m = 480 m. 3 Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
∴ A wins by 20 m.
- 5. In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
Options- A. 21 m
- B. 26 m
- C. 28 m
- D. 29 m Discuss
Correct Answer: 28 m
Explanation:
A : B = 100 : 75B : C = 100 : 96.
∴ A : C = ❨ A x B ❩ = ❨ 100 x 100 ❩ = 100 = 100 : 72. B C 75 96 72 ∴ A beats C by (100 - 72) m = 28 m.
- 6. In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
Options- A. 8 points
- B. 10 points
- C. 14 points
- D. 40 points Discuss
Correct Answer: 10 points
Explanation:
A : B = 100 : 80.A : C = 100 : 72.
∴ B = ❨ B x A ❩ = ❨ 80 x 100 ❩ = 10 = 100 = 100 : 90. C A C 100 72 9 90 ∴ B can give C 10 points.
- 7. In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Options- A. 20 m
- B. 25 m
- C. 22.5 m
- D. 9 m Discuss
Correct Answer: 20 m
Explanation:
Distance covered by B in 9 sec. = ❨ 100 x 9 ❩m = 20 m. 45 ∴ A beats B by 20 metres.
- 8. A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:
Options- A.
1 22 - B.
3 22 - C.
2 91 - D.
2 77
Discuss
Correct Answer:2 91
Explanation:
Let S be the sample space.Then, n(S) = number of ways of drawing 3 balls out of 15 = 15C3 = (15 x 14 x 13) (3 x 2 x 1) = 455. Let E = event of getting all the 3 red balls.
∴ n(E) = 5C3 = 5C2 = (5 x 4) = 10. (2 x 1) ∴ P(E) = n(E) = 10 = 2 . n(S) 455 91 - 9. Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
Options- A.
1 2 - B.
2 5 - C.
8 15 - D.
9 20
Discuss
Correct Answer:9 20
Explanation:
Here, S = {1, 2, 3, 4, ...., 19, 20}.Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
∴ P(E) = n(E) = 9 . n(S) 20 - 10. Two dice are tossed. The probability that the total score is a prime number is:
Options- A.
1 6 - B.
5 12 - C.
1 2 - D.
7 9
Discuss
Correct Answer:5 12
Explanation:
Clearly, n(S) = (6 x 6) = 36.Let E = Event that the sum is a prime number.
Then E = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3),
(5, 2), (5, 6), (6, 1), (6, 5) }∴ n(E) = 15.
∴ P(E) = n(E) = 15 = 5 . n(S) 36 12
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