Part filled in 4 minutes = 4 | ❨ | 1 | + | 1 | ❩ | = | 7 | . |
15 | 20 | 15 |
Remaining part = | ❨ | 1 - | 7 | ❩ | = | 8 | . |
15 | 15 |
Part filled by B in 1 minute = | 1 |
20 |
∴ | 1 | : | 8 | :: 1 : x |
20 | 15 |
x = | ❨ | 8 | x 1 x 20 | ❩ | = 10 | 2 | min = 10 min. 40 sec. |
15 | 3 |
∴ The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec.
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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