4 | 1 | hours |
3 |
Work done by the leak in 1 hour = | ❨ | 1 | - | 3 | ❩ | = | 1 | . |
2 | 7 | 14 |
∴ Leak will empty the tank in 14 hrs.
1 | 13 | hours |
17 |
2 | 8 | hours |
11 |
3 | 9 | hours |
17 |
4 | 1 | hours |
2 |
3 | 9 | hours |
17 |
Net part filled in 1 hour | ❨ | 1 | + | 1 | - | 1 | ❩ | = | 17 | . |
5 | 6 | 12 | 60 |
∴ The tank will be full in | 60 | hours i.e., 3 | 9 | hours. |
17 | 17 |
Part filled by the four taps in 1 hour = | ❨ | 4 x | 1 | ❩ | = | 2 | . |
6 | 3 |
Remaining part = | ❨ | 1 - | 1 | ❩ | = | 1 | . |
2 | 2 |
∴ | 2 | : | 1 | :: 1 : x |
3 | 2 |
⟹ x = | ❨ | 1 | x 1 x | 3 | ❩ | = | 3 | hours i.e., 45 mins. |
2 | 2 | 4 |
So, total time taken = 3 hrs. 45 mins.
Work done by the waste pipe in 1 minute = | 1 | - | ❨ | 1 | + | 1 | ❩ |
15 | 20 | 24 |
= | ❨ | 1 | - | 11 | ❩ |
15 | 120 |
= - | 1 | . [-ve sign means emptying] |
40 |
∴ Volume of | 1 | part = 3 gallons. |
40 |
Volume of whole = (3 x 40) gallons = 120 gallons.
5 |
11 |
6 |
11 |
7 |
11 |
8 |
11 |
6 |
11 |
Part filled by (A + B + C) in 3 minutes = 3 | ❨ | 1 | + | 1 | + | 1 | ❩ | = | ❨ | 3 x | 11 | ❩ | = | 11 | . |
30 | 20 | 10 | 60 | 20 |
Part filled by C in 3 minutes = | 3 | . |
10 |
∴ Required ratio = | ❨ | 3 | x | 20 | ❩ | = | 6 | . |
10 | 11 | 11 |
Part filled by (A + B) in x min. + Part filled by A in (30 -x) min. = 1.
∴ x | ❨ | 2 | + | 1 | ❩ | + (30 - x). | 2 | = 1 |
75 | 45 | 75 |
⟹ | 11x | + | (60 -2x) | = 1 |
225 | 75 |
⟹ 11x + 180 - 6x = 225.
⟹ x = 9.
Part filled in 4 minutes = 4 | ❨ | 1 | + | 1 | ❩ | = | 7 | . |
15 | 20 | 15 |
Remaining part = | ❨ | 1 - | 7 | ❩ | = | 8 | . |
15 | 15 |
Part filled by B in 1 minute = | 1 |
20 |
∴ | 1 | : | 8 | :: 1 : x |
20 | 15 |
x = | ❨ | 8 | x 1 x 20 | ❩ | = 10 | 2 | min = 10 min. 40 sec. |
15 | 3 |
∴ The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec.
Part filled by (A + B) in 1 minute = | ❨ | 1 | + | 1 | ❩ | = | 1 | . |
60 | 40 | 24 |
Suppose the tank is filled in x minutes.
Then, | x | ❨ | 1 | + | 1 | ❩ | = 1 |
2 | 24 | 40 |
⟹ | x | x | 1 | = 1 |
2 | 15 |
⟹ x = 30 min.
Then, faster pipe will fill it in | x | minutes. |
3 |
∴ | 1 | + | 3 | = | 1 |
x | x | 36 |
⟹ | 4 | = | 1 |
x | 36 |
⟹ x = 144 min.
Profit on 1st part Profit on 2nd part | ||
8% | Mean Profit 14% |
18% |
4 | 6 |
Ration of 1st and 2nd parts = 4 : 6 = 2 : 3
∴ Quantity of 2nd kind = | ❨ | 3 | x 1000 | ❩kg | = 600 kg. |
5 |
By rule of alligation, we have:
Cost of 1 kg of Type 1 rice Cost of 1 kg of Type 2 rice | ||
Rs. 15 | Mean Price Rs. x |
Rs. 20 |
(20 - x) | (x - 15) |
∴ | (20 - x) | = | 2 |
(x - 15) | 3 |
⟹ 60 - 3x = 2x - 30
⟹ 5x = 90
⟹ x = 18.
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