6 | 2 | hours |
3 |
7 | 1 | hours |
2 |
(A + B)'s 1 hour's work = | ❨ | 1 | + | 1 | ❩ | = | 9 | = | 3 | . |
12 | 15 | 60 | 20 |
(A + C)'s hour's work = | ❨ | 1 | + | 1 | ❩ | = | 8 | = | 2 | . |
12 | 20 | 60 | 15 |
Part filled in 2 hrs = | ❨ | 3 | + | 2 | ❩ | = | 17 | . |
20 | 15 | 60 |
Part filled in 6 hrs = | ❨ | 3 x | 17 | ❩ | = | 17 | . |
60 | 20 |
Remaining part = | ❨ | 1 - | 17 | ❩ | = | 3 | . |
20 | 20 |
Now, it is the turn of A and B and | 3 | part is filled by A and B in 1 hour. |
20 |
∴ Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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