Then, pipe B will fill it in (x + 6) hours.
∴ | 1 | + | 1 | = | 1 |
x | (x + 6) | 4 |
⟹ | x + 6 + x | = | 1 |
x(x + 6) | 4 |
⟹ x2 - 2x - 24 = 0
⟹ (x -6)(x + 4) = 0
⟹ x = 6. [neglecting the negative value of x]
Then, pipes B and C will take | x | and | x | hours respectively to fill the tank. |
2 | 4 |
∴ | 1 | + | 2 | + | 4 | = | 1 |
x | x | x | 5 |
⟹ | 7 | = | 1 |
x | 5 |
⟹ x = 35 hrs.
Then, | 3x - 9 | = | 12 |
5x - 9 | 23 |
⟹ 23(3x - 9) = 12(5x - 9)
⟹ 9x = 99
⟹ x = 11.
∴ The smaller number = (3 x 11) = 33.
(x x 5) = (0.75 x 8) ⟹ x = | ❨ | 6 | ❩ | = 1.20 |
5 |
Quantity of milk = | ❨ | 60 x | 2 | ❩litres = 40 litres. |
3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
Then, milk : water = | ❨ | 40 | ❩ | . |
20 + x |
Now, | ❨ | 40 | ❩ | = | 1 |
20 + x | 2 |
⟹ 20 + x = 80
⟹ x = 60.
∴ Quantity of water to be added = 60 litres.
A's new salary = | 115 | of 2k = | ❨ | 115 | x 2k | ❩ | = | 23k |
100 | 100 | 10 |
B's new salary = | 110 | of 3k = | ❨ | 110 | x 3k | ❩ | = | 33k |
100 | 100 | 10 |
C's new salary = | 120 | of 5k = | ❨ | 120 | x 5k | ❩ | = 6k |
100 | 100 |
∴ New ratio | ❨ | 23k | : | 33k | : 6k | ❩ | = 23 : 33 : 60 |
10 | 10 |
Part filled in 2 hours = | 2 | = | 1 |
6 | 3 |
Remaining part = | ❨ | 1 - | 1 | ❩ | = | 2 | . |
3 | 3 |
∴ (A + B)'s 7 hour's work = | 2 |
3 |
(A + B)'s 1 hour's work = | 2 |
21 |
∴ C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }
= | ❨ | 1 | - | 2 | ❩ | = | 1 |
6 | 21 | 14 |
∴ C alone can fill the tank in 14 hours.
Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank.
∴ | 1 | + | 1 | = | 1 |
x | (x - 5) | (x - 9) |
⟹ | x - 5 + x | = | 1 |
x(x - 5) | (x - 9) |
⟹ (2x - 5)(x - 9) = x(x - 5)
⟹ x2 - 18x + 45 = 0
(x - 15)(x - 3) = 0
⟹ x = 15. [neglecting x = 3]
Part filled by A in 1 min = | 1 | . |
20 |
Part filled by B in 1 min = | 1 | . |
30 |
Part filled by (A + B) in 1 min = | ❨ | 1 | + | 1 | ❩ | = | 1 | . |
20 | 30 | 12 |
∴ Both pipes can fill the tank in 12 minutes.
6 | 2 | hours |
3 |
7 | 1 | hours |
2 |
(A + B)'s 1 hour's work = | ❨ | 1 | + | 1 | ❩ | = | 9 | = | 3 | . |
12 | 15 | 60 | 20 |
(A + C)'s hour's work = | ❨ | 1 | + | 1 | ❩ | = | 8 | = | 2 | . |
12 | 20 | 60 | 15 |
Part filled in 2 hrs = | ❨ | 3 | + | 2 | ❩ | = | 17 | . |
20 | 15 | 60 |
Part filled in 6 hrs = | ❨ | 3 x | 17 | ❩ | = | 17 | . |
60 | 20 |
Remaining part = | ❨ | 1 - | 17 | ❩ | = | 3 | . |
20 | 20 |
Now, it is the turn of A and B and | 3 | part is filled by A and B in 1 hour. |
20 |
∴ Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.
Part filled by (A + B) in x min. + Part filled by A in (30 -x) min. = 1.
∴ x | ❨ | 2 | + | 1 | ❩ | + (30 - x). | 2 | = 1 |
75 | 45 | 75 |
⟹ | 11x | + | (60 -2x) | = 1 |
225 | 75 |
⟹ 11x + 180 - 6x = 225.
⟹ x = 9.
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