A's new salary = | 115 | of 2k = | ❨ | 115 | x 2k | ❩ | = | 23k |
100 | 100 | 10 |
B's new salary = | 110 | of 3k = | ❨ | 110 | x 3k | ❩ | = | 33k |
100 | 100 | 10 |
C's new salary = | 120 | of 5k = | ❨ | 120 | x 5k | ❩ | = 6k |
100 | 100 |
∴ New ratio | ❨ | 23k | : | 33k | : 6k | ❩ | = 23 : 33 : 60 |
10 | 10 |
Then, first number = 120% of x = | 120x | = | 6x |
100 | 5 |
Second number = 150% of x = | 150x | = | 3x |
100 | 2 |
∴ Ratio of first two numbers = | ❨ | 6x | : | 3x | ❩ | = 12x : 15x = 4 : 5. |
5 | 2 |
Then, 5 : 8 : 15 : x
⟹ 5x = (8 x 15)
x = | (8 x 15) | = 24. |
5 |
Then, 4x - 3x = 1000
⟹ x = 1000.
∴ B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
⟹ | ❨ | 140 | x 5x | ❩ | , | ❨ | 150 | x 7x | ❩ | and | ❨ | 175 | x 8x | ❩ |
100 | 100 | 100 |
⟹ 7x, | 21x | and 14x. |
2 |
∴ The required ratio = 7x : | 21x | : 14x |
2 |
⟹ 14x : 21x : 28x
⟹ 2 : 3 : 4.
Then, sum of their values = Rs. | ❨ | 25x | + | 10 x 2x | + | 5 x 3x | ❩ | = Rs. | 60x |
100 | 100 | 100 | 100 |
∴ | 60x | = 30 | ⟺ x = | 30 x 100 | = 50. |
100 | 60 |
Hence, the number of 5 p coins = (3 x 50) = 150.
Quantity of milk = | ❨ | 60 x | 2 | ❩litres = 40 litres. |
3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
Then, milk : water = | ❨ | 40 | ❩ | . |
20 + x |
Now, | ❨ | 40 | ❩ | = | 1 |
20 + x | 2 |
⟹ 20 + x = 80
⟹ x = 60.
∴ Quantity of water to be added = 60 litres.
(x x 5) = (0.75 x 8) ⟹ x = | ❨ | 6 | ❩ | = 1.20 |
5 |
Then, | 3x - 9 | = | 12 |
5x - 9 | 23 |
⟹ 23(3x - 9) = 12(5x - 9)
⟹ 9x = 99
⟹ x = 11.
∴ The smaller number = (3 x 11) = 33.
Then, pipes B and C will take | x | and | x | hours respectively to fill the tank. |
2 | 4 |
∴ | 1 | + | 2 | + | 4 | = | 1 |
x | x | x | 5 |
⟹ | 7 | = | 1 |
x | 5 |
⟹ x = 35 hrs.
Then, pipe B will fill it in (x + 6) hours.
∴ | 1 | + | 1 | = | 1 |
x | (x + 6) | 4 |
⟹ | x + 6 + x | = | 1 |
x(x + 6) | 4 |
⟹ x2 - 2x - 24 = 0
⟹ (x -6)(x + 4) = 0
⟹ x = 6. [neglecting the negative value of x]
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