If x = | √3 + 1 | and y = | √3 - 1 | , then the value of (x2 + y2) is: |
√3 - 1 | √3 + 1 |
x = | (√3 + 1) | x | (√3 + 1) | = | (√3 + 1)2 | = | 3 + 1 + 2√3 | = 2 + √3. |
(√3 - 1) | (√3 + 1) | (3 - 1) | 2 |
y = | (√3 - 1) | x | (√3 - 1) | = | (√3 - 1)2 | = | 3 + 1 - 2√3 | = 2 - √3. |
(√3 + 1) | (√3 - 1) | (3 - 1) | 2 |
∴ x2 + y2 = (2 + √3)2 + (2 - √3)2
= 2(4 + 3)
= 14
? = 5103 x 121/100
= 61.74.63 = 6000
S.I. on Rs. 240 for half the time = Rs. 10.
T.D. on Rs. 250 = Rs. 10.
∴ T.D. on Rs. 260 = Rs. | ❨ | 10 | x 260 | ❩ | = Rs. 10.40 |
250 |
The circumcentre of a triangle is always the point of intersection of the Bisectors .Hence required answer will be bisectors .
∴ S.I. on Rs. 450 = Rs. 90.
S.I. on Rs. 540 = Rs. | ❨ | 90 | x 540 | ❩ | = Rs. 108. |
450 |
∴ B.D. = Rs. 108.
So, after 63 days, it will be Monday.
∴ After 61 days, it will be Saturday.
Rate of Interest = 12% per annum
Simple Interest =Rs 6000 per annum
Let 'P' is the principal
SI= (P x R x T)/100
where , SI= Simple Interest
T= Time
R= Rate
? 6000=(P x 1 x 12)/100
? P =(6000 x 100)/12
= Rs 50000
Hence the required amount is Rs 50000
Then, AB + BC = 2x metres.
AC = √2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = | ❨ | 0.59x | x 100 | ❩% | = 30% (approx.) |
2x |
Let 'x' be the required number
0.75x + 75 =x
? 0.25x=75
? x=75 / 0.25 =300
A : B = 2 : 3 and B : C = 5 : 8 = | ❨ | 5 x | 3 | ❩ | : | ❨ | 8 x | 3 | ❩ | = 3 : | 24 |
5 | 5 | 5 |
⟹ A : B : C = 2 : 3 : | 24 | = 10 : 15 : 24 |
5 |
⟹ B = | ❨ | 98 x | 15 | ❩ | = 30. |
49 |
Let the number be y.
Then, 35% of y = 112
( 35 / 100 )y = 112
y = ( 112 x 100 ) / 35
= 320
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