Then, (4.20 + 0.40z) - (6.30 + 0.15z) = 0.40
⟹ 0.25z = 0.40 + 2.10
⟹ z = | 2.50 | = | 250 | = 10. |
0.25 | 25 |
∴ X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.
4.2 x 4.2 - 1.9 x 1.9 | is equal to: |
2.3 x 6.1 |
Given Expression = | (a2 - b2) | = | (a2 - b2) | = 1. |
(a + b)(a - b) | (a2 - b2) |
63 |
487 |
119 |
993 |
125 |
999 |
125 |
999 |
0.125125... = 0.125 = | 125 |
999 |
1 | , | 2 | , | 3 | , | 4 | , | 5 | , | 6 |
3 | 5 | 7 | 5 | 6 | 7 |
1 | , | 2 | , | 3 | , | 4 | , | 5 | , | 6 |
3 | 5 | 5 | 7 | 6 | 7 |
1 | , | 2 | , | 3 | , | 4 | , | 5 | , | 6 |
3 | 5 | 5 | 6 | 7 | 7 |
6 | , | 5 | , | 4 | , | 3 | , | 2 | , | 1 |
7 | 6 | 5 | 7 | 5 | 3 |
6 | , | 5 | , | 4 | , | 3 | , | 2 | , | 1 |
7 | 6 | 5 | 7 | 5 | 3 |
= | ❨ | 3 + | 87 | ❩ | - | ❨ | 2 + | 59 | ❩ |
99 | 99 |
= 1 + | ❨ | 87 | - | 59 | ❩ |
99 | 99 |
= 1 + | 28 |
99 |
= 1.28.
.009 | = .01 |
? |
Let | .009 | = .01; Then x = | .009 | = | .9 | = .9 |
x | .01 | 1 |
617.00 6.017 0.617 + 6.0017 -------- 629.6357 ---------
If | 144 | = | 14.4 | , then the value of x is: |
0.144 | x |
144 | = | 14.4 |
0.144 | x |
⟹ | 144 x 1000 | = | 14.4 |
144 | x |
⟹ x = | 14.4 | = 0.0144 |
1000 |
29.94 | = | 299.4 |
1.45 | 14.5 |
= | ❨ | 2994 | x | 1 | ❩ | [ Here, Substitute 172 in the place of 2994/14.5 ] |
14.5 | 10 |
= | 172 |
10 |
= 17.2
34.95 240.016 + 23.98 -------- 298.946 --------
The value of | 0.1 x 0.1 x 0.1 + 0.02 x 0.02 x 0.02 | is: |
0.2 x 0.2 x 0.2 + 0.04 x 0.04 x 0.04 |
Given expression = | (0.1)3 + (0.02)3 | = | 1 | = 0.125 |
23 [(0.1)3 + (0.02)3] | 8 |
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