The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

Then,	5x + 3	=	11
	4x + 3		9

⟹ 9(5x + 3) = 11(4x + 3)

⟹ 45x + 27 = 44x + 33

⟹ 45x - 44x = 33 - 27

⟹ x = 6.

∴ Anand's present age = 4x = 24 years.

Given that:

1. The difference of age b/w R and Q = The difference of age b/w Q and T.

2. Sum of age of R and T is 50 i.e. (R + T) = 50.

Question: R - Q = ?.

Explanation:

R - Q = Q - T

(R + T) = 2Q

Now given that, (R + T) = 50

So, 50 = 2Q and therefore Q = 25.

Question is (R - Q) = ?

Here we know the value(age) of Q (25), but we don't know the age of R.

Therefore, (R-Q) cannot be determined.

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Then,	(6x + 6) + 4	=	11
	(5x + 6) + 4		10

⟹ 10(6x + 10) = 11(5x + 10)

⟹ 5x = 10

⟹ x = 2.

∴ Sagar's present age = (5x + 6) = 16 years.

Let the mother's present age be x years.

Then, the person's present age =	❨	2	x	❩	years.
		5

∴	❨	2	x + 8	❩	=	1	(x + 8)
		5				2

⟹ 2(2x + 40) = 5(x + 8)

⟹ x = 40.

Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.

Let the son's present age be x years. Then, man's present age = (x + 24) years.

∴ (x + 24) + 2 = 2(x + 2)

⟹ x + 26 = 2x + 4

⟹ x = 22.

Let the son's present age be x years. Then, (38 - x) = x

⟹ 2x = 38.

⟹ x = 19.

∴ Son's age 5 years back (19 - 5) = 14 years.

Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,

4x + 6 = 26    ⟺    4x = 20

x = 5.

∴ Deepak's age = 3x = 15 years.

Let Rahul's age be x years.

Then, Sachin's age = (x - 7) years.

∴	x - 7	=	7
	x		9

⟹ 9x - 63 = 7x

⟹ 2x = 63

⟹ x = 31.5

Hence, Sachin's age =(x - 7) = 24.5 years.

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

⟹ 5x = 20

⟹ x = 4.

∴ Age of the youngest child = x = 4 years.