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- Question
A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:
Options- A. 5 days
- B. 6 days
- C. 10 days
- D.
10 1 days 2 - Correct Answer
- 10 days
Explanation(B + C)'s 1 day's work = ❨ 1 + 1 ❩ = 7 . 9 12 36 Work done by B and C in 3 days = ❨ 7 x 3 ❩ = 7 . 36 12 Remaining work = ❨ 1 - 7 ❩ = 5 . 12 12 Now, 1 work is done by A in 1 day. 24 So, 5 work is done by A in ❨ 24 x 5 ❩ = 10 days. 12 12
More questions
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The banker's gain on a certain sum due 1 1 years hence is 3 of the banker's 2 25 discount. The rate percent is:
Options- A.
5 1 % 5 - B.
9 1 % 11 - C.
8 1 % 8 - D.
6 1 % 6
Discuss
Correct Answer:9 1 % 11
Explanation:
Let, B.D = Re. 1.Then, B.G. = Re. 3 . 25 ∴ T.D. = (B.D. - B.G.) = Re. ❨ 1 - 3 ❩ = Re. 22 . 25 25 Sum = ❨ 1 x (22/25) ❩ = Rs. 22 . 1-(22/25) 3 S.I. on Rs. 22 for 1 1 years is Re. 1. 3 2 ∴ Rate = ❨ 100 x 1 ❩% = 100 = 9 1 %. 11 11 22 x 3 3 2 - 2. If two marbles are picked at random, what is the probability that both marbles are red?
Options- A. 1/6
- B. 1/3
- C. 2/15
- D. None of the above Discuss
Correct Answer: None of the above
Explanation:
Total number of marbles = 6 + 4 + 2 + 3 = 15
Ways of selection of two red marbles = n(E) = 6C2
Ways of selection of two marbles = n(S) = 15C2
So, required probability = (6C2) / (15C2)
= (6 x 5) / (15 x 14) = 1/7- 3. A and B together have Rs. 1210. If 4⁄15 of A's amount is equal to ⅖ of B's amount, how much amount does B have?
Options- A. Rs. 460
- B. Rs. 484
- C. Rs. 550
- D. Rs. 664 Discuss
Correct Answer: Rs. 484
Explanation:
4 A = 2 B 15 5 ⟹ A = ❨ 2 x 15 ❩B 5 4 ⟹ A = 3 B 2 ⟹ A = 3 B 2 ⟹ A : B = 3 : 2.
∴ B's share = Rs. ❨ 1210 x 2 ❩ = Rs. 484. 5 - 4. Three taps A, B and C fill a tank in 20 min, 15 min and 12 min, respectively. If all the taps are opened simultaneously, how long will they take to fill 40% of the tank?
Options- A. 1 min
- B. 2 min
- C. 3 min
- D. 4 min Discuss
Correct Answer: 2 min
Explanation:
Part of the tank filled in 1 min by A, B and C = 1/20 + 1/15 +1/12
= (3 + 4 + 5)/60 = 12/60 = 1/5
? Time taken by A, B and C to fill the tank = 5 min
? Time taken by A, B and C to fill 40% of the tank = 40% of 5 = (40/100) x 5 = 2 min.- 5. When 0.252525...........is converted into a fraction, then find the result.
Options- A. 25/99
- B. 25/90
- C. 25/999
- D. 25/9999 Discuss
Correct Answer: 25/99
Explanation:
0.252525 ..... = 0.25= 25/99
- 6. The sides of a triangle area in the ratio of 1/3 : 1/4 : 1/5 and its perimeter is 94 cm.
Find the length of the smallest side of the triangle .
Options- A. 18 cm
- B. 22.5 cm
- C. 24 cm
- D. 27 cm Discuss
Correct Answer: 24 cm
Explanation:
Given ratio = 1/3 : 1/4 : 1/5 = 20 : 15 : 12
Let length of the sides be 20k, 15k and 12k.
Then, according to the question,
20k + 15k + 12k = 94
? 47k = 94
? k = 94/47 = 2
Smallest side = 12k = 12 x 2 = 24 cm- 7. The salary of A, B, C, D, E is Rs. 8000, Rs. 5000, Rs. 11000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is
Options- A. Rs. 7000
- B. Rs. 8000
- C. Rs. 8500
- D. Rs. 9000 Discuss
Correct Answer: Rs. 8000
Explanation:
Average salary
= 8000 + 5000 + 11000 + 7000 + 9000 / 5
= Rs. 8000- 8. The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is:
Options- A. 20
- B. 30
- C. 40
- D. None of these Discuss
Correct Answer: 20
Explanation:
Let the numbers be a, b and c.Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131.
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138 + 2 x 131 = 400.
⟹ (a + b + c) = √400 = 20.
- 9. Neeta borrowed some money at the rate of 6% per annum for the first 3 yr. at the rate of 9% per annum for the next 5 yr and a the rate of 13% per annum for the period beyond 8 yr. If she pays a total interest of ? 8160 at the and of 11 yr how much money did she borrow?
Options- A. ? 12000
- B. ? 10000
- C. ? 8000
- D. Data is inadequate Discuss
Correct Answer: ? 8000
Explanation:
Let the sum borrowed = P
Then, according to the question,
[(P x 6 x 3)/100] + [(P x 9 x 5)/100] + [(P x 13 x 3)/100] = 8160
? (18P + 45P +39P) / 100 = 8160
? 102P/100 = 8160
? P = (8160 x 100)/102
? P = ? 8000- 10. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Options- A. 50 m
- B. 72 m
- C. 80 m
- D. 82 m Discuss
Correct Answer: 50 m
Explanation:
Let the length of each train be x metres.Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
= ❨ 10 x 5 ❩m/sec 18 = ❨ 25 ❩m/sec 9 ∴ 2x = 25 36 9 ⟹ 2x = 100
⟹ x = 50.
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